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zavuch27 [327]
3 years ago
13

Cellular respiration is? (Single choice.)

Chemistry
1 answer:
Taya2010 [7]3 years ago
5 0
The answer would be A
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How do you convert the measured mass of a substance to moles?
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What is the name of the movement of the Earth around the Sun as pointed out by letter J.
MAVERICK [17]

it is called the Earth's rotation
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What Happens When extra Solute is added to unsaturated ,saturated and supersaturated solution​
Ymorist [56]

of water is 36.0 g. If any more NaCl is added past that point, it will not dissolve because the solution is saturated. If more solute is added and it does not dissolve, then the original solution was saturated. If the added solute dissolves, then the original solution was unsaturated.

8 0
2 years ago
What is the pH of 0.166 M triethylammonium chloride, (C2H5)3NHCl. The Kb of triethylamine, (C2H5)3N, is 5.2 x 10-4.?
777dan777 [17]

Answer:

5.7

Explanation:

(C₂H₅)₃NHCl dissociates according to the following equation.

(C₂H₅)₃NHCl ⇒ (C₂H₅)₃NH⁺ + Cl⁻

The molar ratio of (C₂H₅)₃NHCl to (C₂H₅)₃NH⁺ is 1:1. Then, the concentration of (C₂H₅)₃NH⁺ is Ca = 0.166 M.

(C₂H₅)₃NH⁺ is the conjugate acid of (C₂H₅)₃N. Given the Kb of (C₂H₅)₃N, we can calculate Ka for (C₂H₅)₃NH⁺ using the following expression.

Ka × Kb = Kw

Ka = Kw / Kb

Ka = 1.0 × 10⁻¹⁴ / 5.2 × 10⁻⁴

Ka = 1.9 × 10⁻¹¹

(C₂H₅)₃NH⁺ dissociates according to the following equation.

(C₂H₅)₃NH⁺ ⇄ (C₂H₅)₃N + H⁺

We can calculate [H⁺] using the following expression.

[H⁺] = √(Ca × Ka) = √(0.166 × 1.9 × 10⁻¹¹) = 1.8 × 10⁻⁶

The pH is:

pH = -log [H⁺] = -log 1.8 × 10⁻⁶ = 5.7

7 0
2 years ago
Aluminum chloride, AlCl3, is an inexpensive reagent used in many industrial processes. It is made by treating scrap aluminum wit
mylen [45]

Answer:

83.8%

Explanation:

The balanced reaction equation is;

2Al(s) + 3Cl2(g) → 2AlCl3(s)

Now we have to obtain the limiting reactant as the reactant that produces the least amount of AlCl3

Amount of Al = 3.11g/27 g/mol = 0.115 moles

If 2 moles of Al yields 2 moles of  AlCl3

Then 0.115 moles of Al yields 0.115 moles of  AlCl3

For Cl2

Amount of Cl2 = 5.32 g/71 g/mol= 0.075 moles

If 3 moles of Cl2 yields 2 moles of  AlCl3

0.075 moles of Cl2 yields 0.075   * 2/3 = 0.05 moles of  AlCl3

Hence Cl2 is the limiting reactant

Theoretical yield of  AlCl3 = 0.05 moles of  AlCl3 * 133g/mol = 6.65 g

%yield = actual yield /theoretical yield * 100

%yield = 5.57 g/6.65 g * 100

%yield = 83.8%

4 0
2 years ago
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