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zavuch27 [327]
3 years ago
13

Cellular respiration is? (Single choice.)

Chemistry
1 answer:
Taya2010 [7]3 years ago
5 0
The answer would be A
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A forensic chemist is given a white powder for analysis. She dissolves 0.50 g of the substance in 8.0 g of benzene. The solution
Sholpan [36]

Answer:

The given compound cannot be cocaine.

Explanation:

The chemist can comment on the nature of compound being cocaine or not from the depression in freezing point.

Depression in freezing point of is related to molality as:

Depression in freezing point = Kf X molality

Where

Kf = cryoscopic constant = 4.90°C/m

depression in freezing point = normal freezing point - freezing point of solution

depression in freezing point = 5.5-3.9 = 1.6°C

1.6°C = 4.90 X molality

molality=\frac{1.6}{4.90} = 0.327 m

we know that:

molality=\frac{moles}{mass of solvent(kg)}=\frac{moles}{0.008kg}

therefore

moles = 0.327X0.008 = 0.00261 mol

moles=\frac{mass}{molarmass}

molarmass=\frac{mass}{moles}=\frac{0.50}{0.00261}= 191.57g/mol

The molar mass of cocaine is 303.353

So the given compound cannot be cocaine.

3 0
3 years ago
A 8 kg cat is running 4 m/s. How much kinetic energy does it have
Debora [2.8K]
<span>KE = 1/2mv^2
KE = 1/2(8)4 m/s^2
KE = 4*4
KE = 16 Joules

Kinetic energy would equal 16 J 
</span>
8 0
2 years ago
The ionic equations represent the reactions between four metals, P, Q, R and S, and solutions of the salts of the same metals
EleoNora [17]

Answer:

P + Q2+ -> no reaction

R + P2+ -> R2+ + P

Q + S2+ -> Q2+ + S

S + P2+ -> S2+ + P

S + R2+ -> S2+ + R

S + Q2+ -> no reaction

What is the correct order of reactivity of the metals?

Most -----------------------> least

A. P R S Q

B. Q R S P

C. Q S R P

D. S Q P Rhhgu

5 0
3 years ago
A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an
mr_godi [17]

Answer : The value of equilibrium constant (K) is, 424.3

Explanation :  Given,

Concentration of H_2 at equilibrium = 0.067 mol

Concentration of CO at equilibrium = 0.021 mol

Concentration of CH_3OH at equilibrium = 0.040 mol

The given chemical reaction is:

CO+2H_2\rightarrow CH_3OH

The expression for equilibrium constant is:

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

Now put all the given values in this expression, we get:

K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}

K_c=424.3

Thus, the value of equilibrium constant (K) is, 424.3

4 0
3 years ago
How many branches of chemistry are there .​
faltersainse [42]

Answer:

5

Explanation:

Analytical chemistry

Organic chemistry

Inorganic chemistry

physical chemistry

Biochemistry

6 0
2 years ago
Read 2 more answers
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