The independent variable is the one we are changing in the experiment. As we change it, the dependent variable might also change.
C. the density of the rock because we are changing the density of the rock and seeing how all other variables change with regards to the density.
Answer:
0.02 M
Explanation:
Given data:
Mass of sodium carbonate = 1.8 g
Volume of water = 862 cm³ (862/1000 = 0.862 L)
Concentration = ?
Solution:
Formula:
Concentration = number of moles / volume in L
Number of moles of sodium carbonate:
Number of moles = mass/molar mass
Number of moles = 1.8 g/ 106 g/mol
Number of moles = 0.02 mol
Concentration:
c = 0.02 mol / 0.862 L
c = 0.02 M
The energy would be 3.31*10-19J
Answer:
4.1 mol·L⁻¹
Explanation:
You are diluting the solution with water, so you can use the dilution formula
c₁V₁ = c₂V₂ Divide each side by V₂
c₂ = c₁ × V₁/V₂
Data:
c₁ = 7.0 mol·L⁻¹; V₁ = 2.5 L
Water added = 1.5 L
Calculations:
(a) <em>New volume
</em>
V₂ = 2.5 L + 1.8 L
= 4.3 L
(b) <em>New concentration
</em>
c₂ = 7.0 × 2.5/4.3
= 7.0 × 0.581
= 4.1 mol·L⁻¹
Answer:
0.474 moles of C₆H₆OS
Explanation:
Step 1: Write the balanced equation
2 C₆H₆OS + 11 O₂ ⇒ 12 CO + 6 H₂O + 2 SO₃
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of C₆H₆OS to SO₃ is 2:2.
Step 3: Calculate the moles of C₆H₆OS reacted if 0.474 moles of SO₃ are produced
We will use the previously established molar ratio.
0.474 mol SO₃ × 2 mol C₆H₆OS/2 mol SO₃ = 0.474 mol C₆H₆OS