Question

A horse gallops for 3.5 minutes around the raceing track. During this time it changes velocity from 543 min to 628 min. Calculate the acceleration of the horse during this 3.5min interval

Answer 1

Answer:

The acceleration of the horse during this time interval is 24.286 m/min²

Explanation:

Given;

initial velocity of the horse during the gallop, u = 543 m /min

final velocity of the horse during the gallop, v = 628 m /min

time of motion, t = 3.5 minutes

The acceleration of the horse is given by the change in velocity per change in time;

$a = \frac{v-u}{t}\\\\a = \frac{628-543}{3.5}\\\\a = 24.286 \ m/min^2$

Therefore, the acceleration of the horse during this time interval is 24.286 m/min²