if a sine wave representing ac voltage has an effective value of 70 vac what would be the waves peak value

Physics

1 answer:

Morgarella [4.7K]4 years ago

3 0

Answer:

99 V

Explanation:

The effective voltage of an AC current (also called rms voltage) is given by

$V_{rms} = \frac{V_0}{\sqrt{2}}$

where

Vrms is the rms voltage

V0 is the peak voltage

In this problem, we know the effective voltage:

$V_{rms} = 70 V$

Therefore, we can re-arrange the equation to find the peak voltage:

$V_0 = V_{rms} \sqrt{2} =(70 V)(\sqrt{2})=99 V$

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A plastic block of mass 0.20.2kg is initially at rest on a horizontal frictionless surface. A bullet of mass 1212 g is fired wit

Juli2301 [7.4K]

Answer:

94.29619%

Explanation:

$m_1$ = Mass of bullet= 0.012 kg

$m_2$ = Mass of block = 0.2 kg

$u_1$ = Initial Velocity of bullet= 550 m/s

$u_2$ = Initial Velocity of block = 0 m/s

$v_1$ = Final Velocity of bullet = 20 m/s

$v_2$ = Final Velocity of block

As the linear momentum of the system is conserved

$m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}\\\Rightarrow v_2=\dfrac{0.012\times 550+0.2\times 0-0.012\times 20}{0.2}\\\Rightarrow v_2=31.8\ m/s$

Change in kinetic energy is given by

$\Delta K=\dfrac{1}{2}(m_1u_1^2-m_1v_1^2-m_2v_2^2)\\\Rightarrow \Delta K=\dfrac{1}{2}(0.012\times 550^2-0.012\times 20^2-0.2\times 31.8^2)\\\Rightarrow \Delta K=1711.476\ J$