The balanced equation is
<span>2 C6H6 +15 O2 = 12 CO2 + 6 H2O </span>
<span>the ratio between C6H6 and CO2 is 2 : 12 </span>
<span>moles CO2 produced = 7.94 x 12 / 2 =47.6</span>
That practice is over that day?
Answer:
1083.6 g
Explanation:
At STP, 1 mol of any given mass will occupy 22.4 L.
With the information above in mind we can<u> calculate how many moles of nitrogen gas (N₂) are there in 867 L</u>:
- 867 L ÷ 22.4 L/mol = 38.7 mol
Finally we convert 38.7 moles of N₂ into grams, using its molar mass:
- 38.7 mol * 28 g/mol = 1083.6 g
a) 1 mole of Ne
b) i/2 mole of Mg
c) 1570 moles of Pb.
d) 2.18125*10^-13 moles of oxygen.
Explanation:
The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.
6.23*10^23= 1/ 6.23*10^23
= 1 mole
The number of moles calculated by Avogadro's number in 3.01*10^23 of Mg
3.2*10^23=1/6.23*10^23
= 1/2 moles of Pb.
Number of moles in 3.25*10^5 gm of lead.
atomic weight of Pb=
n=weight/atomic weight
= 3.25*10^5/ 207
= 1570 moles of Pb.
Number of moles 4.50 x 10-12 g O
number of moles= 4.50*10^-12/16
= 2.18125*10^-13 moles of oxygen.
A higher temperature makes the particles move faster, that makes them collide more often. The answer would be this: "It increases the average kinetic energy and number of collisions per minute."
