Answer:
The solution is given below.
Explanation:
Speed = Distance(m)/Time(sec.)
Distance traveled = 150 m
Time taken = 3.5 seconds
Speed of car = 150/3.5 = 42.86 m/s
So the car traveled at a speed of 42.86 m/s.
Answer:
0.382 atm
Explanation:
In order to find the pressure, you need to know the moles of carbon dioxide (CO₂) gas. This can be found by multiplying the mass (g) by the molar mass (g/mol) of CO₂. It is important to arrange the conversion in a way that allows for the cancellation of units.
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
15 grams CO₂ 1 mole
---------------------- x ------------------------ = 0.341 moles CO₂
44.007 grams
To find the pressure, you need to use the Ideal Gas Law equation.
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
After you convert Celsius to Kelvin, you can plug the given and calculated values into the equation and simplify to find the pressure.
P = ? atm R = 0.08206 atm*L/mol*K
V = 20 L T = 0 °C + 273.15 = 273.15 K
n = 0.341 moles
PV = nRT
P(20 L) = (0.341 moles)(0.08206 atm*L/mol*K)(273.15 K)
P(20 L) = 7.64016
P = 0.382 atm
2.55 moles H20 will be produced
Answer:
1,816 L
Explanation:
Molar concentration or molarity is a way to express the concentration of a chemical in terms of moles of substances per liter of solution.
To obtain the liters of this solution you must convert moles/L to g/L with formula weight (FW), thus:
0,1107 mol of KCl / L × (74,6 g / mol) = 8,258 g of KCl / L.
It means that in one liter you have 8,258 g of KCl. Thus, 15,00 g of KCl are contained in:
15,00 g × (1 L / 8,258 g) = 1,816 L
I hope it helps!
Answer:
C₆H₆
Explanation:
Molar mass of the compound is 78g/mol
Unknown:
Molecular formula of the compound = ?
Solution:
The empirical formula of the compound is CH.
Empirical formula is the simplest formula of a compound.
To solve this problem:
Find the molar mass of CH;
Molar mass = 12 + 1 = 13g/mol
Multiplication index =
= 6
So;
(CH)₆ ;
Therefore:
C₆H₆