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weqwewe [10]
3 years ago
14

On the Kelvin temperature scale, which value approximately represents the freezing point of water?

Chemistry
1 answer:
kupik [55]3 years ago
8 0

Answer: freezing point of water 273.15K, boiling point of water 373.15 K

Explanation:

The Kelvin scale starts at the lowest possible temperature, absolute zero. This is 0 Kelvins (K)= -273.15 deg C. Hence water freezes at 0 deg C = 273.15 K and boils at 100 deg C = 373.15 K

You might be interested in
A car travels 150 meters in 3.5 seconds what is its speed?
defon

Answer:

The solution is given below.

Explanation:

Speed   = Distance(m)/Time(sec.)

Distance traveled = 150 m

Time taken = 3.5 seconds

Speed of car = 150/3.5 = 42.86 m/s

So the car traveled at a speed of 42.86 m/s.

6 0
3 years ago
Question 9
Evgesh-ka [11]

Answer:

0.382 atm

Explanation:

In order to find the pressure, you need to know the moles of carbon dioxide (CO₂) gas. This can be found by multiplying the mass (g) by the molar mass (g/mol) of CO₂. It is important to arrange the conversion in a way that allows for the cancellation of units.

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

15 grams CO₂               1 mole
----------------------  x  ------------------------  =  0.341 moles CO₂
                                44.007 grams

To find the pressure, you need to use the Ideal Gas Law equation.

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

After you convert Celsius to Kelvin, you can plug the given and calculated values into the equation and simplify to find the pressure.

P = ? atm                              R = 0.08206 atm*L/mol*K

V = 20 L                               T = 0 °C + 273.15 = 273.15 K

n = 0.341 moles

PV = nRT

P(20 L) = (0.341 moles)(0.08206 atm*L/mol*K)(273.15 K)

P(20 L) = 7.64016

P = 0.382 atm

7 0
2 years ago
How many moles of water can be produced from the reaction of 28g of C3H8
Montano1993 [528]
2.55 moles H20 will be produced
7 0
3 years ago
How many liters of 0.1107 M KCI contain 15.00 g of KCI (FW 74.6 g/mol)? O0.02227 L O 0.5502 L 01661 L O 1.816 L 18.16 L
Greeley [361]

Answer:

1,816 L

Explanation:

Molar concentration or molarity is a way to express the concentration of a chemical in terms of moles of substances per liter of solution.

To obtain the liters of this solution you must convert moles/L to g/L with formula weight (FW), thus:

0,1107 mol of KCl / L × (74,6 g / mol) = 8,258 g of KCl / L.

It means that in one liter you have 8,258 g of KCl. Thus, 15,00 g of KCl are contained in:

15,00 g × (1 L / 8,258 g) = 1,816 L

I hope it helps!

3 0
3 years ago
The empirical formula of a hydrocarbon (compound that contains only C and H is found to be CH. laboratory procedures have found
gulaghasi [49]

Answer:

C₆H₆

Explanation:

Molar mass of the compound is 78g/mol

Unknown:

Molecular formula of the compound  = ?

Solution:

The empirical formula of the compound is CH.

Empirical formula is the simplest formula of a compound.

To solve this problem:

 Find the molar mass of CH;

       Molar mass = 12 + 1  = 13g/mol

Multiplication index  = \frac{78}{13}    = 6

So;

              (CH)₆  ;

 Therefore:

               C₆H₆

6 0
3 years ago
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