Answer:
The volume is 406 mL
Explanation:
Step 1: Data given
Molarity of a zinc nitrate solution = 1.3 M
Mass of zinc nitrate = 100 grams
Molar mass of Zn(NO3)2 = 189.36 g/mol
Step 2: Calculate moles Zn(NO3)2
Moles Zn(NO3)2 = mass Zn(NO3)2 / molar mass Zn(NO3)2
Moles Zn(NO3)2 = 100.0 grams / 189.36 g/mol
Moles Zn(NO3)2 = 0.5281 moles
Step 3: Calculate volume
Molarity = moles / volume
Volume = moles / molarity
Volume = 0.5281 moles / 1.3 M
Volume = 0.406 L = 406 mL
The volume is 406 mL
So what do you want me to do
Explanation
Answer:
It might be responding variable.
Answer:
molar mass of methane CH4
= C + 4 H
= 12.0 + 4 x 1.008
= 12.0 + 4.032
= 16.042g/mol
7.31 x 10^25 molecules x 1 mole CH4 = 121.43 moles
6.02 x 10^23 CH4 molecules
121.43 moles CH4 are present.
Explanation:
not to certain if this is right or not.. but hope it helps!
Answer:
The correct answer is 2.75 grams of HCl.
Explanation:
The given balanced equation is:
CaCO₃ (s) + 2HCl (aq) ⇒ CaCl₂ (aq) + H₂O (l) + CO₂ (g)
Based on the given information, one mole of calcium carbonate is reacting with two moles of HCl. The molecular mass of HCl is 36.5 grams, thus, the mass of 2 moles of HCl will be, 36.5 × 2 = 73 grams
The molecular mass of CaCO₃ is 100 gram per mole, that is, the mass of 1 mole of CaCO₃ is 100 grams, therefore, the mass of HCl required for reacting with 3.75 grams of CaCO₃ will be,
= 3.75 × 2 × 36.5 / 100 = 2.74 grams of HCl.
