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Marta_Voda [28]
3 years ago
13

Goat gallops at -1.5m/s, how far will the goat travel in 20 seconds? Please show work

Physics
1 answer:
saw5 [17]3 years ago
5 0

Answer:

30m

Explanation:

Given parameters:

Speed of the goat  = 1.5m/s

Time  = 20s

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use;

      Speed  = \frac{distance}{time}  

 Distance = Speed x time

 So;

 Distance  = 1.5m/s x 20s  = 30m

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If an object has a mass of 20 grams and a volume of 40 cm3, what is its density in g/cm3?
alexgriva [62]
20/40=0.5 g/cm^3 becuase, mass/volume=density.
8 0
3 years ago
A ball rolls along the floor with a constant velocity of 6m/s how far it have to gone after 50 seconds
Alika [10]
50(6)=300.
The ball traveled 300 meters in 50 seconds.
Hope this helps and please give brainliest!
8 0
4 years ago
How can a small spark start a huge explosion? using electric forces and molecules
OLga [1]

Answer:

Small sparks can lead to huge explosion if they are left unattended.

Explanation:

Small sparks are not harmful but if these sparks happen near some hazardous material or object then it could lead to heavy explosion. If there is some chemical substance near the spark or there are magnetic lines which can explode the spark then these minor sparks could result in heavy disastrous explosion.

4 0
3 years ago
A 5.0-kg rock and a 3.0 × 10−4-kg pebble are held near the surface of the earth.(a)Determine the magnitude of the gravitational
a_sh-v [17]

Answer:

a). Determine the magnitude of the gravitational force exerted on each by the earth.

Rock: F = 49.06N

Pebble: F = 29.44N

(b)Calculate the magnitude of the acceleration of each object when released.

Rock: a =9.8m/s^{2}

Pebble:  a =9.8m/s^{2}

Explanation:

The universal law of gravitation is defined as:

F = G\frac{m1m2}{r^{2}}  (1)

Where G is the gravitational constant, m1 and m2 are the masses of the two objects and r is the distance between them.

<em>Case for the rock </em>m = 5.0 Kg<em>:</em>

m1 will be equal to the mass of the Earth m1 = 5.972×10^{24} Kg and since the rock and the pebble are held near the surface of the Earth, then, r will be equal to the radius of the Earth r = 6371000m.

F = (6.67x10^{-11}kg.m/s^{2}.m^{2}/kg^{2})\frac{(5.972x10^{24} Kg)(5.0 Kg)}{(6371000 m)^{2}}

F = 49.06N

Newton's second law can be used to know the acceleration.

F = ma

a =\frac{F}{m} (2)

a =\frac{(49.06 Kg.m/s^{2})}{(5.0 Kg)}

a =9.8m/s^{2}

<em>Case for the pebble </em>m = 3.0 Kg<em>:</em>

F = (6.67x10^{-11}kg.m/s^{2}.m^{2}/kg^{2})\frac{(5.972x10^{24} Kg)(3.0 Kg)}{(6371000 m)^{2}}

F = 29.44N

a =\frac{F}{m}

a =\frac{(29.44 Kg.m/s^{2})}{(3.0 Kg)}

a =9.8m/s^{2}

3 0
3 years ago
Read 2 more answers
An environmentally-conscious student is breaking the rings from a six-pack drink holder before disposing of it. This reduces the
katrin2010 [14]

Answer: seen below.

Explanation:

Firstly we need to remember what exothermic reaction is in thermodynamics. exothermic reaction describes a process or reaction that releases energy from the system to its surroundings, usually in the form of heat, but also in a form of light, sound, or electricity.

In this scenario, due to the heating up nature noticed by the ring during breaking shows that energy is being released to the surrounding in the form of heat which suggest it being an exothermic reaction.

8 0
3 years ago
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