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Masja [62]
4 years ago
6

A ball rolls along the floor with a constant velocity of 6m/s how far it have to gone after 50 seconds

Physics
1 answer:
Alika [10]4 years ago
8 0
50(6)=300.
The ball traveled 300 meters in 50 seconds.
Hope this helps and please give brainliest!
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Which of the following is an example of a renewable natural resource?
borishaifa [10]

Answer:

c. lumber      

Explanation:

Lumber is considered a renewable natural resource because it is gotten from trees and trees are grow-able. A renewable natural resource is a resource which can be used repeatedly and replaced naturally. Examples of renewable natural resources are solar energy from the sun, water, oxygen, biomass, trees etc. Trees can be harvested and processed into lumber. The harvested trees can be planted again by humans or they can naturally reproduce through seedlings or fruits that drop and germinate on their own. This renewable germinating process of trees makes lumber a renewable natural resource.

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3 years ago
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Vaselesa [24]
<h2><u>Answer:</u></h2><h2>A. Displacement</h2><h2>B. Time</h2><h2 /><h2>Your Welcome ❤</h2>
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3 years ago
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A torque of 36.5 N · m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result
vivado [14]

Answer:

21.6\ \text{kg m}^2

3.672\ \text{Nm}

54.66\ \text{revolutions}

Explanation:

\tau = Torque = 36.5 Nm

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 10.3 rad/s

t = Time = 6.1 s

I = Moment of inertia

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_1 t\\\Rightarrow \alpha_1=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha_1=\dfrac{10.3-0}{6.1}\\\Rightarrow \alpha_1=1.69\ \text{rad/s}^2

Torque is given by

\tau=I\alpha_1\\\Rightarrow I=\dfrac{\tau}{\alpha_1}\\\Rightarrow I=\dfrac{36.5}{1.69}\\\Rightarrow I=21.6\ \text{kg m}^2

The wheel's moment of inertia is 21.6\ \text{kg m}^2

t = 60.6 s

\omega_i = 10.3 rad/s

\omega_f = 0

\alpha_2=\dfrac{0-10.3}{60.6}\\\Rightarrow \alpha_1=-0.17\ \text{rad/s}^2

Frictional torque is given by

\tau_f=I\alpha_2\\\Rightarrow \tau_f=21.6\times -0.17\\\Rightarrow \tau=-3.672\ \text{Nm}

The magnitude of the torque caused by friction is 3.672\ \text{Nm}

Speeding up

\theta_1=0\times t+\dfrac{1}{2}\times 1.69\times 6.1^2\\\Rightarrow \theta_1=31.44\ \text{rad}

Slowing down

\theta_2=10.3\times 60.6+\dfrac{1}{2}\times (-0.17)\times 60.6^2\\\Rightarrow \theta_2=312.03\ \text{rad}

Total number of revolutions

\theta=\theta_1+\theta_2\\\Rightarrow \theta=31.44+312.03=343.47\ \text{rad}

\dfrac{343.47}{2\pi}=54.66\ \text{revolutions}

The total number of revolutions the wheel goes through is 54.66\ \text{revolutions}.

3 0
3 years ago
The wattage of a bulb is 24 W when it is connected to a 12 V battery. Calculate its effective wattage if it operates on a 6 V ba
tresset_1 [31]
It would be 12W because: 6v is half of 12v so half of 24w would be 12w
3 0
3 years ago
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what is the angular speed w of the system immediately after the collision in terms f the sstem parameters and I
denis23 [38]

Answer: hello some part of your question is missing attached below is the missing detail

answer :

<em>w</em>f = M( v cos∅ )D / I

Explanation:

The Angular speed <em>wf  </em>of the system after collision in terms of the system parameters  and I can be expressed as

considering angular momentum conservation

Li = Lf

M( v cos∅ ) D = ( ML^2 / 3  + mD^2 ) <em>w</em>f

where ;  ( ML^2 / 3  + mD^2 ) = I ( Inertia )

In terms of system parameters and I

<em>w</em>f = M( v cos∅ )D / I

5 0
3 years ago
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