¿Qué valor tiene la resistencia eléctrica de un cable de cobre, si por él viaja una carga de 100 [C] en 60 segundos, si se encue
1 answer:
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From the theory we know that:
c = λ / T
f = 1 / T
Where:
c = 3. / m (the speed of light)
λ is the wavelengh (in meters)
T is the period (in seconds)
f is the frequency (in Hz)
We were told that:
f = 7.30 .
And we want to find out the value of λ.
c = λ / T
c = λ . 1/T
Swaping 1/T = f
c = λ . f
λ = c / f
λ = 3 . / 7.30 .
λ = 4.12 m
Response: 4.12 m = 412 nm
:-)
Answer:
v=39.05 m/s
Explanation:
Given that
x= 56 cm
F= 158 N
m= 58 g = 0.058 kg
Lets take spring constant = k
At the initial position,before releasing the arrow
F= k x
By putting the values
F= k x
158= 0.56 k
k=282.14 N/m
Now from energy conservation
Lets take final speed of the arrow after releasing
k x²=mv²
282.14 x 0.56² = 0.058 v²
v=39.05 m/s