Total number of orders served by Maya, Ahmad and Joe on Moday = 75
Let the number of orders Maya served be x.
Then :
Number of orders Joe served = 2x
Number of orders Ahmad served = x - 5
This can be written in an equation as :
Which means :
Number of orders Joe served :
= 2 × 20
= 40
Thus, Joe served 40 orders.
Number of orders Maya served = 20
Number of orders Ahmad served :
= 20 - 5
= 15
Thus, Ahmad served 15 orders.
<h2>Therefore, </h2>
- Maya served 20 orders
- Ahmad served 15 orders
- Joe served 40 orders.
SOLUTION:
A box has a square base of side x and height y where x,y > 0.
Its volume is V = x^2y and its surface area is
S = 2x^2 + 4xy.
(a) If V = x^2y = 12, then y = 12=x^2 and S(x) = 2x^2 C 4x (12=x2) = 2x2 + 48x^-1. Solve S'(x) = 4x - 48x-2 = 0 to
obtain x = 12^1/3. Since S(x/) ---> infinite as x ---> 0+ and as x --->infinite, the minimum surface area is S(12^1/3) = 6 (12)^2/3 = 31.45,
when x = 12^1/3 and y = 12^1/3.
(b) If S = 2x2 + 4xy = 20, then y = 5^x-1 - 1/2 x and V (x) = x^2y = 5x - 1/2x^3. Note that x must lie on the closed interval [0, square root of 10]. Solve V' (x) = 5 - 3/2 x^2 for x>0 to obtain x = square root of 30 over 3 . Since V(0) = V (square root 10) = 0 and V(square root 30 over 3) = 10 square root 30 over 9 , the
maximum volume is V (square root 30 over 3) = 10/9 square root 30 = 6.086, when x = square root 30 over 3 and y = square root 30 over 3 .
The answer is: <span>(2x² + 2x)/(5x - 2)
</span>
Option D. B
When a point is reflected across the x-axis, (x, y) becomes (-x, y)
Because A (2, 4) and B (-2, 4) are like (x, y) and (-x, y), we know that Option D is the answer.
6&7. Also -7,-6 is the correct answer
