Answer:
0.0815
Explanation:
Mechanical advantage is output force/input force. So all you have to do is 55.0N/675N ~ 0.0815
Hope this helped!
Answer:
Ah good question um no u dont have to be near it its a vr thing ur gonna have it on u the whole time. You can only be a few feet away from ur tv if u chose to do it on there or u can do it on ur phone but its also the same distance.
Explanation:
Answer: 63% of the final charge
Explanation:
When a capacitor is connected to a battery/power supply, the capacitor charges following the exponential law:
![Q(t)=Q_0 (1-e^{-\frac{t}{\tau}})](https://tex.z-dn.net/?f=Q%28t%29%3DQ_0%20%281-e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%7D%29)
where
is the final charge of the capacitor, which is
![Q_0 =CV_0](https://tex.z-dn.net/?f=Q_0%20%3DCV_0)
where C is the capacitance and
the potential difference of the battery
t is the time
is the time constant of the circuit
Re-writing the equation,
![Q(t)=CV_0 (1-e^{-\frac{t}{\tau}})](https://tex.z-dn.net/?f=Q%28t%29%3DCV_0%20%281-e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%7D%29)
After a time equal to one time constant,
![t=\tau](https://tex.z-dn.net/?f=t%3D%5Ctau)
Therefore the charge on the capacitor will be
![Q(\tau)=CV_0 (1-e^{-\frac{\tau}{\tau}})=CV_0(1-e^{-1})=0.63CV_0](https://tex.z-dn.net/?f=Q%28%5Ctau%29%3DCV_0%20%281-e%5E%7B-%5Cfrac%7B%5Ctau%7D%7B%5Ctau%7D%7D%29%3DCV_0%281-e%5E%7B-1%7D%29%3D0.63CV_0)
Which means 63% of the final charge.
Answer:2.5 mph
Explanation:
Total time for trip=6 hr
Speed of roy=5 mph
the trip 4 miles one side
Let v be the stream velocity
time=![\frac{distance}{speed}](https://tex.z-dn.net/?f=%5Cfrac%7Bdistance%7D%7Bspeed%7D)
![6=\frac{4}{5+v}+\frac{4}{5-v}](https://tex.z-dn.net/?f=6%3D%5Cfrac%7B4%7D%7B5%2Bv%7D%2B%5Cfrac%7B4%7D%7B5-v%7D)
![6=4\left [ \frac{1}{5-v}+\frac{1}{5+v}\right ]](https://tex.z-dn.net/?f=6%3D4%5Cleft%20%5B%20%5Cfrac%7B1%7D%7B5-v%7D%2B%5Cfrac%7B1%7D%7B5%2Bv%7D%5Cright%20%5D)
![1.5=\left [\frac{5+v+5-v}{\left ( 5+v\right )\left (5-v \right )} \right ]](https://tex.z-dn.net/?f=1.5%3D%5Cleft%20%5B%5Cfrac%7B5%2Bv%2B5-v%7D%7B%5Cleft%20%28%205%2Bv%5Cright%20%29%5Cleft%20%285-v%20%5Cright%20%29%7D%20%5Cright%20%5D)
![75-3v^2=20](https://tex.z-dn.net/?f=75-3v%5E2%3D20)
![v=\sqrt{\frac{55}{3}}\approx 2.5mph](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B55%7D%7B3%7D%7D%5Capprox%202.5mph)
Answer:
As it moves farther and farther away from Q, it's speed will keep increasing.
Explanation:
This is so because the point charges are both positive charges and positive charges repel.
As the charges repel, they do so at an increasing speed.