Answer:
The intensity increased by a factor of 158489
Explanation:
Given that,
Sound level = 95.0 dB
Sound level = 43.0 dB
Frequency = 10000 Hz
We need to calculate the ratio of sound intensity
Using formula of sound level

Put the value into the formula
...(I)
.....(II)
Subtracting these equations


Taking inverse log

Hence, The intensity increased by a factor of 158489
Answer:
Acceleration = 2.35 m/
Speed = 8.67 m/s
Explanation:
The coefficient of friction , u =0.3
The angle of incline = 30°
The two forces acting on block are weight and friction.
weight along the incline = mg cos60° =
= 0.5 mg
Friction along incline = umg cos30° = mg 
Friction along incline = 0.26 mg
Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg
Acceleration =
= 0.24 g = 2.35 m/
The height of incline = 8 m
Length of the inclined edge = 16 m


v= 8.67 m/s
Ca(NO3)2(aq) + Na2CO3(aq) → 2NaNO3 + CaCO3⬇. NaNO3 is solution so CaCO3 is the precipitate formed.
Answer:i One way to solve the quadratic equation x2 = 9 is to subtract 9 from both sides to get one side equal to 0: x2 – 9 = 0. The expression on the left can be factored:
Explanation: