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Greeley [361]
3 years ago
14

Please help!

Mathematics
1 answer:
earnstyle [38]3 years ago
4 0
It’s c!! i’m glad i could help! have an amazing day love
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A point in the figure is selected at random. Find the probability that the point will be in the part that is NOT shaded.
vitfil [10]

Answer:

About 20%

Step-by-step explanation:

The probability of a point on the un-shaded region will be given by;

Area of the shaded region/total area  

Considering that the circles are of the same size, then the length of the square is 2d

Area of the square = 4d²

Area of the shaded = (4d² -4π(d/2)²

= 4d² -πd², but π = 22/7

= 6/7d²

Probability = (6/7d² ÷ 4d²) × 100%

= (6/28 d²) × 100%

= 21.42 %

So your answer is B. 20%

Don't thank me this was easy.

3 0
3 years ago
The authors of a paper presented a correlation analysis to investigate the relationship between maximal lactate level x and musc
Volgvan

Answer:

Which is the output of the formula =AND(12>6;6>3;3>9)?

A.

TRUE

B.

FALSE

C.

12

D.

9

Step-by-step explanation:

4 0
3 years ago
What does 5 mean? What is the value of 5
Leto [7]
5? Did you mean to insert a picture
5 0
3 years ago
Read 2 more answers
How do you decide whether substitution is the best method to solve a system in three variables?
Ivan
<span>Select one equation and solve it for one of its variables.
In the other equation, substitute for the variable just solved.
Solve the new equation. 
<span>Substitute the value found into any equation involving both variables and solve for the other variable. </span></span>
3 0
3 years ago
Jason bought 10 of the 30 raffle tickets for a drawing. What is the probability that Jason will win all 3 of the prizes if once
anastassius [24]

For the first drawing, there are  30  tickets altogether, and Jason
has  10  of them.  The probability that one of his tickets will win is

                                                               10 / 30 .

For the second drawing, there are  29  tickets altogether, and Jason
has  9  of them.  The probability that one of his tickets will win is

                                                                 9 / 29 .

For the third drawing, there are  28  tickets altogether, and Jason
has  8  of them.  The probability that one of his tickets will win is

                                                                 8 / 28 .

The probability that all three of these things will happen is

                      (10/30) x (9/29) x (8/28)  =  720 / 24,360

                                                             =  6 / 203  =  2.96 percent (rounded)    

7 0
3 years ago
Read 2 more answers
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