Answer: Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.
Explanation:
According to Gay-Lussac's Law : 'The pressure of the gas increases with increase in temperature of the gas when volume of the gas is kept constant'.
At constant volume, pressure of the gas will decrease on decreasing the temperature or vice versa.
Decreasing the temperature inside the container will decrease the pressure of a gas inside a closed cubical container.
<span>In a solid the atoms are tightly packed together and vibrate in place, in a liquid the atoms are loosely packed together and can move past each other,
extra: and in a gas the atoms are far apart and move freely and </span><em>
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Answer:
electric balance, goggles, beaker
Explanation:
I did it and got it right
Answer:
K = 3.45
Explanation:
In the reaction:
SO₂(g) + NO₂(g) ⇄ SO₃(g) + NO(g)
And K is:
K = [SO₃] [NO] / [SO₂] [NO₂]
<em>Where [] are concentrations in equilibrium, as volume is 1L, [] could be taken as moles.</em>
Equilibrium concentrations are:
[SO₂] = 2.00 moles - X
[NO₂] = 2.00 moles - X
[SO₃] = X
[NO] = X
AS moles of NO are 1.3 moles, X = 1.3 moles
Replacing:
[SO₂] = 0.7 moles = 0.7M
[NO₂] = 0.7M
[SO₃] = 1.3M
[NO] = 1.3M
K = 1.3M² / 0.7M²
<h3>K = 3.45</h3>
