Answer: the ball will have a charge of 8x10^8C when we remove 5x10^27 electrons.
Explanation:
If the sphere is neutral, then the charge of the sphere is 0C
Now, when we remove an electron (-1.6*10^-19 C) we are subtracting a negative number, so the new charge of the sphere is: 1.6*10^-19 C
Now, for N removed electrons, the charge of the sphere is:
N*1.6*10^-19 C
We want to find the number N when:
N*1.6*10^-19 C = 8.0x 10^8 C
N = (8.0/1.6)x10^(8 + 19) = 5x10^27 electrons.
<span>According to the Biot-Savart law, the magnetic field produced by a moving charge will be zero at a point in back of. The correct option among all the options that are given in the question is the second option or option "b". I hope that this answer has actually come to your help.</span>
Answer:
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Answer
given,
frequency = 523 Hz
piano tuner hears = 2.00 beats/s
a) possible frequency = 523 ± 2
525 Hz and 521 Hz
b) On tightening piano wire, tension will be increased which will cause an increase of frequency of piano wire. Since no. of beats heard is also increased, the frequency of piano wire must be greater than the frequency of oscillator.
f p' = 5+ f₀
f p' = 3 + 523 Hz = 526 Hz.
c) f = k x √T
Let the tension at 523 Hz be T₀ and at 526 Hz it be T₁
523 = k x √T₀
T₀ = 523²/ k²
T₁ = 526²/ k²
% change in tension
= 
= 
= 1.13 %
