Ask question

Ask question

All categories

kolbaska11 [484]

3 years ago

6

In Seattle's speech, he states, "Yonder sky has wept tears of compassion on our fathers for centuries untold".This statement is

an example of

2 answers:

77julia77 [94]3 years ago

5 0

It is an example of personification because personification is when human traits are give to non human things. Sky's cannot cry.

aniked [119]3 years ago

5 0

Answer is Personification. I've taken the test.

You might be interested in

The Pasig Revolving Tower has an estimated height of 45.23 meters. How high is it in yard?

hichkok12 [17]

Answer:

50.26

I hope its help

Thank you

6 0

3 years ago

Sort out electric current as fundamental or derived unit.

Gemiola [76]

Answer:

electric current is derived unit.

Explanation:

According to the definition of electric current, it appears to be a derived quantity. Charge on the other hand seems more fundamental than electric current.

7 0

3 years ago

Read 2 more answers

A man slides on snow without friction starting at 8.96m/s at the top of an inclined plane with height 8.21m. What is his speed a

hammer [34]

Answer:

V2 = 15.53 [m/s]]

Explanation:

In order to solve this problem we must use the principle of energy conservation, where potential energy is transformed into kinetic energy. At the bottom is taken as a reference level of potential energy, where the value of this energy is equal to zero.

Above the inclined plane we have two energies, kinetics and potential. While when the sled is at the reference level all this energy will have been transformed into kinetic energy.

$E_{1}=E_{2}\\ m*g*h+(\frac{1}{2} )*m*v_{1} ^{2}=\frac{1}{2}*m*v_{2} ^{2} \\(9.81*8.21)+(0.5*8.96^{2} )=(0.5*v_{2}^{2} )\\(0.5*v_{2}^{2} )=120.68\\v_{2} ^{2}=241.36\\v_{2} =\sqrt{241.36}\\ v_{2} =15.53[m/s]$

4 0

3 years ago

Last question guys help

natulia [17]

Answer:

I think the first reply me if I'm wrong sorry hehe

3 0

3 years ago

A 110 kg football player running with a velocity of 5.0 m/s hits another stationary football

KengaRu [80]

Answer:

The final velocity of the second player is 6.1 m/s.

Explanation:

The final velocity of the second player can be calculated by conservation of linear momentum (p):

$p_{i} = p_{f}$

$m_{a}v_{a_{i}} + m_{b}v_{b_{i}} = m_{a}v_{a_{f}} + m_{b}v_{b_{f}}$ (1)

Where:

$m_{a}$ : is the mass of the first football player = 110 kg

$m_{b}$ : is the mass of the second football player = 90 kg

$v_{a_{i}}$ : is the initial velocity of the first football player = 5.0 m/s

$v_{b_{i}}$ : is the initial velocity of the second football player = 0 (he is at rest)

$v_{a_{f}}$ : is the final velocity of the first football player = 0 (he stops after the impact)

$v_{b_{f}}$ : is the final velocity of the second football player =?

By solving equation (1) for $v_{b_{f}}$ we have:

$110 kg*5.0 m/s + 0 = 0 + 90 kg*v_{b_{f}}$

$v_{b_{f}} = \frac{110 kg*5.0 m/s}{90 kg} = 6.1 m/s$

Therefore, the final velocity of the second player is 6.1 m/s.

I hope it helps you!

8 0

3 years ago