Answer:
With sonar, what happens to sound pulses from a ship after they hit the ocean floor? ... They bounce back to the ship.
Explanation:
To solve this problem we will apply the concepts related to the Force of gravity given by Newton's second law (which defines the weight of an object) and at the same time we will apply the Hooke relation that talks about the strength of a body in a system with spring.
The extension of the spring due to the weight of the object on Earth is 0.3m, then
![F_k = F_{W,E}](https://tex.z-dn.net/?f=F_k%20%3D%20F_%7BW%2CE%7D)
![kx_1 = mg](https://tex.z-dn.net/?f=kx_1%20%3D%20mg)
The extension of the spring due to the weight of the object on Moon is a value of
, then
![kx_2 = mg_m](https://tex.z-dn.net/?f=kx_2%20%3D%20mg_m)
Recall that gravity on the moon is a sixth of Earth's gravity.
![kx_2 = m\frac{g}{6}](https://tex.z-dn.net/?f=kx_2%20%3D%20m%5Cfrac%7Bg%7D%7B6%7D)
![kx_2 = \frac{1}{6} mg](https://tex.z-dn.net/?f=kx_2%20%3D%20%5Cfrac%7B1%7D%7B6%7D%20mg)
![kx_2 = \frac{1}{6} kx_1](https://tex.z-dn.net/?f=kx_2%20%3D%20%5Cfrac%7B1%7D%7B6%7D%20kx_1)
![x_2 = \frac{1}{6} x_1](https://tex.z-dn.net/?f=x_2%20%3D%20%5Cfrac%7B1%7D%7B6%7D%20x_1)
We have that the displacement at the earth was
, then
![x_2 = \frac{1}{6} 0.3](https://tex.z-dn.net/?f=x_2%20%3D%20%5Cfrac%7B1%7D%7B6%7D%200.3)
![x_2 = 0.05m](https://tex.z-dn.net/?f=x_2%20%3D%200.05m)
Therefore the displacement of the mass on the spring on Moon is 0.05m
Answer:
The pendulum frequency is (c) the same, or very close to it
Explanation:
The simple pendulum corresponds to a simple harmonic movement, to reach this approximation in the expression of the force the sine of the angle (θ) approaches an angle value, this is only true for small angles, generally less than 15º
Sine (15th) = 0.2588
The angle in radians is 15º π / 180º = 0.26180.2588 / 0.2618
The difference between these two values is less than 1.2%
for smaller angle the difference is reduced more
Therefore, the period for both the 5º and 10º angles is almost the same
Answer:![32.77\ mi/hr](https://tex.z-dn.net/?f=32.77%5C%20mi%2Fhr)
Explanation:
Given
Initially Reading on the odometer is ![31,500\ miles](https://tex.z-dn.net/?f=31%2C500%5C%20miles)
Final reading on the odometer is ![31,713\ miles](https://tex.z-dn.net/?f=31%2C713%5C%20miles)
Time taken is ![t=6.5\ hr](https://tex.z-dn.net/?f=t%3D6.5%5C%20hr)
average velocity ![=\dfrac{\text{Displacement}}{\text{time}}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B%5Ctext%7BDisplacement%7D%7D%7B%5Ctext%7Btime%7D%7D)
![v_{avg}=\dfrac{31713-31500}{6.5}](https://tex.z-dn.net/?f=v_%7Bavg%7D%3D%5Cdfrac%7B31713-31500%7D%7B6.5%7D)
![v_{avg}=\dfrac{213}{6.5}](https://tex.z-dn.net/?f=v_%7Bavg%7D%3D%5Cdfrac%7B213%7D%7B6.5%7D)
![v_{avg}=32.77\ mi/hr](https://tex.z-dn.net/?f=v_%7Bavg%7D%3D32.77%5C%20mi%2Fhr)
Thus the average velocity of mail truck is ![32.77\ mi/hr](https://tex.z-dn.net/?f=32.77%5C%20mi%2Fhr)
Answer:
Temperature affects phase change by slowing down the movement in between the atoms, thus causing a change in kinetic energy, which in turn causes the atoms to undergo forms of combining or a type of disepersion.
Explanation:
Kinetic energy while being the reason phase changes are constant, Kinetic Energy can be caused by other means. Pressure and temperature can affect many other states kinetic energy, which in turn can affect each state of matter. Making a group of atoms or compounds compacts will force the atoms to move closer together thus with a lower net kinetic energy energy. Reducing temperature also works along the same lines. Colder temperatures can slow down atomic movements which in turn will naturally make each atom move close to each other.
With all of the information provided, it is only feasible that pressure and temperature are directly corresponding with the matter and atomic phase change