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3 years ago

What is overtraining?

Physics

2 answers:

larisa86 [58]3 years ago

3 0

Answer:

A - overloading the muscles too often

Explanation:

I Got It Right On Edge :)

Anna11 [10]3 years ago

3 0

Answer:

A. overloading the muscles too often

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How can you show positive body languages with your mouth

sergey [27]

By just smiling. It normally makes you look more happy.And if your happy that's positive body languge

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3 years ago

The figure shows a 100-kg block being released from rest from a height of 1.0 m. It then takes it 0.90 s to reach the floor. Wha

Anna007 [38]

Answer:

The mass of the another block is 60 kg.

Explanation:

Given that,

Mass of block M= 100 kg

Height = 1.0 m

Time = 0.90 s

Let the mass of the other block is m.

We need to calculate the acceleration of each block

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$1.0=0+\dfrac{1}{2}\times a\times(0.90)^2$

$a=\dfrac{2\times1.0}{(0.90)^2}$

$a=2.46\ m/s^2$

We need to calculate the mass of the other block

Using newton's second law

The net force of the block M

$Ma=Mg-T$

$T=Mg-Ma$ ....(I)

The net force of the block m

$ma=T-mg$

Put the value of T from equation (I)

$ma=Mg-Ma-mg$

$m(a+g)=M(g-a)$

$m=\dfrac{M(g-a)}{(a+g)}$

Put the value into the formula

$m=\dfrac{100(9.8-2.46)}{2.46+9.8}$

$m=59.8\ \approx60\ kg$

Hence, The mass of the another block is 60 kg.

8 0

3 years ago

A car speedometer has a 4% uncertainty. What is the range of possible speeds (in km/h) when it reads 110 km/h?

Kruka [31]

4% of 110 is 4.4. So the possible range of speeds is the interval from 110-4.4 till 110+4.4.
105.6 till 114.4

4 0

3 years ago

A chair of weight 70.0 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F =

Annette [7]

Answer:

94.67 N

Explanation:

Consider a free body diagram with force, F of 41 N applied at an angle of 37 degrees while the weight acts downwards. Resolving the force into vertical and horizontal components, we obtain a free body diagram attached.

At equilibrium, normal reaction is equal to the sum of the weight and the vertical component of the force applied. Applying the condition of equilibrium along the vertical direction.

$\begin{array}{l}\\\Sigma {F_y} = 0\\\\N - W - F\sin \theta = 0\\\\N = W + F\sin \theta \\\end{array}$

Substituting 70 N for W, 41 N for F and $\theta$ for 37 degrees

N=70+41sin37=94.67441595 N and rounding off to 2 decimal places

N=94.67 N

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4 years ago

What newton equal to in terms of units of mass and acceleration

Korvikt [17]

This equation is one of the most useful in classical physics. It is a concise statement of Isaac Newton's Second Law of Motion, holding both the proportions and vectors of the Second Law. It translates as: The net force on an object is equal to the massof the object multiplied by the acceleration of the object.

4 0

3 years ago

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