Question

The earplug can reduce the sound level to about 18 decibels (dB). What percentage reduction is this intensity?

Answer 1

Answer:

1 x 10 -10 whisper at 1m distance.

Explanation:

• Properly fitted ear plugs an reduce noise form 15-30db. Although they are better for low frequency

Answer 2

Answer:

The change in intensity is 63%.

Explanation:

intensity level = 18 db

Let the intensity is I.

Io = 10^(-12) W/m^2

Use the formula of intensity

$dB = 10 log\left ( \frac{I}{Io} \right )\\\\18 = 10 log\left ( \frac{I}{Io} \right )\\\\1.8 = log\left ( \frac{I}{Io} \right )\\\\\left ( \frac{I}{Io} \right )=63.1$

So, the change in intensity is 63%.