Answer:
a)3000ohm
b)4.44mA
Explanation:
a) we were given a Nine tree lights connected inparallel across 120-V potential difference, since the resistor are in parallel we use the expresion below
1/R(total)= 1/R₁ + 1/R₂ + 1/R₃ + 1/R₃ +.... 1/R₉
But according to ohm'law which can be expressed below
V=IR
R=V/I
R(total)= 120/0.36
= 333.33ohm
1/R(total)= 1/R₁ + 1/R₂ + 1/R₃ + 1/R₃ +.... 1/R₉
R₁=R₂ =R₃ =R₄= R₅=R₆=R₇=R₈=R₉
1/R(total)=9/R
1/333.33= 9/R
R= 3000ohm
Therefore, the resistance is 3000ohm
b)the bulbs were connected in series here, then for series connection we use below expression
R₁=R₂ =R₃ =R₄= R₅=R₆=R₇=R₈=R₉
R(total)=9R
= 9*3000
=27000ohm
I=VR
I=V/R
I= 120/27000
= 4.44*10⁻³A
4.44mA
Therefore, the current is 4.4mA
Answer:
Melting tin and then cooling it into a mold
Explanation:
When you melt something, and when it cools it returns to its physical state, therefore the physical changes are reversible. For example, take chocolate. When chocolate melts its liquid, then when it's in a colder situation it becomes solid again and so on, the changes are reversible.
The electric field strength of a uniform electric field is constant throughout the field. A perfectly uniform electric field has no variations in the entire field and is unattainable in the real world. However, two parallel plates can generate a field that resembles a perfectly uniform field with slight variations near the edge of the plates. <span>Electric fields are represented by drawing field lines that represent the direction of the field, as well as the strength of the field. More field lines represents a higher field strength. In a non-uniform electric field, the field lines tend to be curved and are more concentrated near the charges. In a uniform electric field, since the field strength does not vary, the field lines are parallel to each other and equally spaced. Uniform fields are created by setting up a potential difference between two conducting plates placed at a certain distance from one another. The field is considered to be uniform at the center of the plates, but varies close to the edge of the plates. The strength of the field depends on the potential difference applied to the plates and the distance by which they are separated. A higher potential difference or voltage results in a stronger electric field. The greater the distance between the plates, the weaker the field becomes. The electric field is therefore calculated as a ratio of the voltage between the plates to the distance they are separated by.</span>
A: decreases in specific heat capacity
The final velocity of the skateboarder I after the collision is 3 m/s to the left.
<h3>
Velocity of skateboarder I</h3>
The velocity of skateboarder I is determined from the principle of conservation of linear momentum.
m1u1 + m2u2 = m1v1 + m2v2
50(0) + 75(0) = 50v1 + 75(2)
0 = 50v1 + 150
v1 = (-150)/50
v1 = - 3
v1 = 3 m/s to the left
Thus, the final velocity of the skateboarder I after the collision is 3 m/s to the left.
Learn more about linear momentum here: brainly.com/question/7538238
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