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kupik [55]
3 years ago
15

A group of students worked in the school garden. The graph shows the number of hours the students worked

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0
A
Rirhrhhrjrjrjrjuriujfhc
xxMikexx [17]3 years ago
5 0
B. 2 hours
I believe it is
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Cold antoje help me answering this please :).<br>Fake answer will be reported. ​
Harrizon [31]

Answer:

158.1

Step-by-step explanation:

Distance is the square root of (x1-x2)^2+(y1-y2)^2

square root of (-4-146)^2+(2-52)^2

square root of 150^2+50^2

square root of 22500+2500

square root of 25000

50sqrt10

Rounding is 158.1

5 0
3 years ago
Sloane kicked a soccer ball at a speed of 56 feet per second. If the ball never leaves the ground, then it can be represented by
aksik [14]

Answer:

Third option: t=3.5\ seconds

Step-by-step explanation:

Given the function:

 H(t)=-16t^2 +56t

 Since the ball never leaves the ground, you need to  substitute H(t)= 0 in the function in order to determine the time the soccer ball traveled:

0=-16t^2 +56t

Factorizing, you get:

0=-8t(2t-7)

Then:

0=-8t\\\\t=0\ seconds\\\\\\\\0=2t-7\\\\7=2t\\\\t=3.5\ seconds

Therefore the time the ball traveled was:

t=3.5\ seconds

3 0
3 years ago
5k-2(3k + 4) = 5x + 4<br> help?
vazorg [7]
Use distributive property
5k - 6k -8 = 5x + 4
Combine like terms
-k - 8 = 5x + 4
add 8 to both sides
-k = 5x + 12
k = -5x- 12
4 0
3 years ago
Read 2 more answers
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e.  \mu=61 and \sigma=9

To find :  The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and 34+3(9).

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between \mu and \mu+3(\sigma). (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between \mu and \mu+3(\sigma) = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0
3 years ago
PLEASE HELP ANSWER FOR BRAINLIEST AND *EXPLAIN* :)
Gnesinka [82]
Since it’s supplementary the straight line would equal to 180 degrees

4d - 1 + 105 = 180
4d + 104 = 180
4d = 76
d = 19
7 0
3 years ago
Read 2 more answers
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