A group of students worked in the school garden. The graph shows the number of hours the students worked

Mathematics

2 answers:

Viefleur [7K]3 years ago

7 0

A
Rirhrhhrjrjrjrjuriujfhc

xxMikexx [17]3 years ago

5 0

B. 2 hours
I believe it is

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This should be easy but plz explain in the best way thank u

pentagon [3]

Answer:

The answer is 1.

Step-by-step explanation:

9^15 = 205891132094649

205891132094649(1/205891132094649 )

Cancel the common factor of "205891132094649 "

You are left with 1.

3 0

3 years ago

A room is 12cm long, 7cm wide and<br>4cm high find the area <br>the ceiling

aksik [14]

Hey there!
I think that it safe to say that this room is a rectangular prism. Therefore, the top and bottom (floor and ceiling) have the same area. We see that our floor dimensions are 12 cm long and 7 cm wide. This also applies to the ceiling. Let’s take our two sides and multiply then to find our area.

12(7)=84

Therefore, the area is 84 square centimeters.

I hope that this helps!

5 0

3 years ago

Read 2 more answers

A professor went to a website for rating professors and looked up the quality rating and also the "easiness" of the six full-tim

Marat540 [252]

We are asked to determine the correlation factor "r" of the given table. To do that we will first label the column for "Quality" as "x" and the column for "Easiness" as "y". Like this:

Now, we create another column with the product of "x" and "y". Like this:

Now, we will add another column with the squares of the values of "x". Like this:

Now, we add another column with the squares of the values of "y":

Now, we sum the values on each of the columns:

Now, to get the correlation factor we use the following formula:

$r=\frac{n\Sigma xy-\Sigma x\Sigma y}{\sqrt{(n\Sigma x^2-(\Sigma x)^2)(n\Sigma y^2-(\Sigma y)^2)}}$

Where:

$\begin{gathered} \Sigma xy=\text{ sum of the column of xy} \\ \Sigma x=\text{ sum of the column x} \\ \Sigma y=\text{ sum of the column y} \\ \Sigma x^2=\text{ sum of the column x\textasciicircum2} \\ \Sigma y^2=\text{ sum of the column y\textasciicircum2} \\ n=\text{ number of rows} \end{gathered}$

Now we substitute the values, we get:

$r=\frac{\left(6)(70.56)-(25.2)(16.4\right)}{\sqrt{((6)(107.12)-(25.2)^2)((6)(47.82)-(16.4)^2)}}$

Solving the operations:

$r=0.858$

Therefore, the correlation factor is 0.858. If the correlation factor approaches the values of +1, this means that there is a strong linear correlation between the variables "x" and "y" and this correlation tends to be with a positive slope.