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Virty [35]
3 years ago
8

What is the main problem with renewable energy sources?

Chemistry
2 answers:
8090 [49]3 years ago
8 0

Answer:

biggest problem with mainstream renewable energy is intermittency.

Artist 52 [7]3 years ago
5 0

Answer:

the biggest problem with mainstream renewable energy is intermittency.

Wind power is only generated when it's windy.

Solar power is only generated when it's sunny.

This creates several fundamental issues.

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In which part of a plant cell does photosynthesis occur?
IrinaVladis [17]

Answer:

<h2>leaves,</h2>

Hope it helps....⋋✿ ⁰ o ⁰ ✿⋌(・o・)

6 0
3 years ago
Read 2 more answers
For each solution, determine the p-values for each ion indicated. A solution that is 0.493 M in NaCl and 0.314 M in NH 4 Cl .
miss Akunina [59]

Complete Question:

Ions to calculate the p-values: Na⁺, Cl⁻, and NH₄⁺

Answer:

pNa = 0.307

pCl = 0.093

pNH₄ = 0.503

Explanation:

The p-value is calculated by the antilog of the concentration of the substance of interest. For example, pH = -log[H⁺]. Thus, first, let's find the ions concentration.

Both substances are salts that solubilize completely, thus, by the solution reactions:

NaCl → Na⁺ + Cl⁻

NH₄Cl → NH₄⁺ + Cl⁻

So, for both reactions the stoichiometry is 1:1:1 and the concentration of the ions is equal to the concentration of the salts.

[Na⁺] = 0.493 M

[Cl⁻] = 0.493 + 0.314 = 0.807 M

[NH₄⁺] = 0.314 M

The p-values are:

pNa = -log[Na⁺] = -log(0.493) = 0.307

pCl = -log[Cl⁻] = -log(0.807) = 0.093

pNH₄ = -log[NH₄⁺] = -log(0.314) = 0.503

7 0
3 years ago
0.0145 moles of helium gas are introduced into a balloon so that the volume of the balloon is 2.54 liters. An additional amount
olga_2 [115]

Answer:

4.43L is final volume of the ballon

Explanation:

Avogadro's law of ideal gases states that <em>equal volumes of gases, at the same temperature and pressure, have the same number of molecules</em>.

The formula is:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

Where V and n are volume and moles of the gas in initial and final conditions.

If the initial conditions are 0.0145 moles and 2.54L and final amount of moles is 0.0253moles, final volume is:

\frac{2.54L}{0.0145mol} =\frac{V_2}{0.0253mol}

V₂ = <em>4.43L is final volume of the ballon</em>

6 0
3 years ago
Commercial cold packs often contain solid NH4NO3 and a pouch of water. The temperature of the pack drops as the NH4NO3 dissolves
Yanka [14]

Answer: b. \Delta H_{soln} is positive and \Delta S_{soln} is positive.

Explanation:-

As the temperature of the pack drops, the energy has been absorbed from the pack for dissolution of NH_4NO_3 in water. Thus as the energy has been absorbed in the reaction, the reaction is endothermic and the change in enthalpy i.e. \Delta H_{soln} is positive.

The entropy is the measure of degree of randomness. The entropy increases when the randomness increases and the entropy decreases when the randomness decreases. When a substance dissolves in water, it dissociate into ions and hence the randomness increases thus the change in entropy i.e. \Delta S_{soln}  is positive.

NH_4NO_3\rightarrow NH_4^++NO_3^-

7 0
3 years ago
A steel beam that is 7.00 m long weighs 326 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending
GrogVix [38]

Answer:

The answer to the question is

Suki is 1.12 m close to the end of the steel beam before the beam begins to tip

Explanation:

To solve the question we list out the known variables first

Length of steel beam, L = 7.00 m

Weight  of steal beam W = 326 N

Distance between supports = 3.00 m

Weight of Suki = 555 N

By moments theory, the sum of moments about a point = 0

and assuming the steal beam is uniform, the weight of the beam will act at the center of the beam

As described the supports are 2.00 m from each end of the beam thus

taking moments about one of the support with Suki between  the end of the beam and the support we have

Distance from center of beam to support = 1.5 m

Distance of Suki to the nearest support = x m

therefore 555 × x + 326 × 1.5 = 0

or x = -0.881 m on the other side of the support

Therefore Suki is (2 - 0.881) m or 1.12 m close to the end before the beam begins to tip

7 0
3 years ago
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