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3 years ago

What is the main problem with renewable energy sources?

Chemistry

2 answers:

8090 [49]3 years ago

8 0

Answer:

biggest problem with mainstream renewable energy is intermittency.

Artist 52 [7]3 years ago

5 0

Answer:

the biggest problem with mainstream renewable energy is intermittency.

Wind power is only generated when it's windy.

Solar power is only generated when it's sunny.

This creates several fundamental issues.

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Which of the following is NOT a chemical change?

nataly862011 [7]

Answer:

Melting butter

Explanation:

You can reverse the change of butter back to its original state but you can never reverse the rest back to there original state

4 0

3 years ago

HELPPPP. SHOW WORK

nekit [7.7K]

I think The answer to two is it would sink

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3 years ago

In a motion diagram the size of the object must be less than the distance moved t or f

KATRIN_1 [288]

The awnser is false.

6 0

3 years ago

Read 2 more answers

Titanium has an HCP crystal structure, a c/a ratio of 1.669, an atomic weight of 47.87 g/mol, and a density of 4.51 g/cm3. Compu

IrinaK [193]

Answer : The atomic radius for Ti is, $1.45\times 10^{-8}cm$

Explanation :

Atomic weight = 47.87 g/mole

Avogadro's number $(N_{A})=6.022\times 10^{23} mol^{-1}$

First we have to calculate the volume of HCP crystal structure.

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times V}$ .............(1)

where,

$\rho$ = density = $4.51g/cm^3$

Z = number of atom in unit cell (for HCP = 6)

M = atomic mass = 47.87 g/mole

$(N_{A})$ = Avogadro's number

V = volume of HCP crystal structure = ?

Now put all the values in above formula (1), we get

$4.51g/cm^3=\frac{6\times (47.87g/mol)}{(6.022\times 10^{23}mol^{-1}) \times V}$

$V=1.06\times 10^{-22}cm^3$

Now we have to calculate the atomic radius for Ti.

Formula used :

$V=6R^2c\sqrt{3}$

Given:

c/a ratio = 1.669 that means, c = 1.669 a

Now put (c = 1.669 a) and (a = 2R) in this formula, we get:

$V=6R^2\times (1.669a)\sqrt{3}$

$V=6R^2\times (1.669\times 2R)\sqrt{3}$

$V=(1.669)\times (12\sqrt{3})R^3$

Now put all the given values in this formula, we get:

$1.06\times 10^{-22}cm^3=(1.669)\times (12\sqrt{3})R^3$

$R=1.45\times 10^{-8}cm$

Therefore, the atomic radius for Ti is, $1.45\times 10^{-8}cm$

3 0

3 years ago

An indicator was used to test a water solution with a pH of 12. Which indicator color would be observed?

juin [17]

Answer:

4) pink phenolphthalein

Explanation:

5 0

3 years ago