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3 years ago

What is the main problem with renewable energy sources?

Chemistry

2 answers:

8090 [49]3 years ago

8 0

Answer:

biggest problem with mainstream renewable energy is intermittency.

Artist 52 [7]3 years ago

5 0

Answer:

the biggest problem with mainstream renewable energy is intermittency.

Wind power is only generated when it's windy.

Solar power is only generated when it's sunny.

This creates several fundamental issues.

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When a pure substance melts does its particles get larger

ziro4ka [17]

I think so ( for solids ) because you know when you melt chocolate it turns into a liquid and liquids allways move around together and it can't get smaller either so, I think you are right.

4 0

4 years ago

In water, oxygen shares a bond with two hydrogen atoms. oxygen is more ____________ than hydrogen, making the bond ____________

arlik [135]

Oxygen is more ELECTRONEGATIVE than Hydrogen, which means that the electrons in the atom are coaxed more toward the Central Oxygen atom. Because of this, the charge is not evenly distributed among the molecule, causing it to have positive and negative sides. This is what we call a POLAR molecule.

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3 years ago

1. Do you believe we can bring an end to acid rain? How so?

Akimi4 [234]

Answer:

Emissions from Electricity. ...

Vehicle Emissions. ...

Reducing Electricity Consumption. ...

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3 years ago

Sulfur dioxide, SO 2 ( g ) , can react with oxygen to produce sulfur trioxide, SO 3 ( g ) , by the reaction 2 SO 2 ( g ) + O 2 (

aleksley [76]

Answer: The amount of heat produced by the reaction is -21.36 kJ

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]$

For the given chemical reaction:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(SO_3(g))})]-[(2\times \Delta H_f_{(SO_2(g))})+(1\times \Delta H_f_{(O_2(g))})]$

We are given:

$\Delta H_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H_f_{(SO_3(g))}=-395.7kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2\times (-395.7))]-[(2\times (-296.8))+(1\times (0))]\\\\\Delta H_{rxn}=-197.8kJ/mol$

To calculate the number of moles, we use ideal gas equation, which is:

$PV=nRT$

where,

P = pressure of the gas = 1.00 bar

V = Volume of the gas = 2.67 L

n = number of moles of gas = ?

R = Gas constant = $0.0831\text{ L. bar }mol^{-1}K^{-1}$

T = temperature of the mixture = $25^oC=[25+273]K=298K$

Putting values in above equation, we get:

$1.00bar\times 2.67L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1\times 2.67}{0.0831\times 298}=0.108mol$

To calculate the heat released of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat released = ?

n = number of moles = 0.108 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -197.8 kJ/mol

Putting values in above equation, we get:

$-197.8kJ/mol=\frac{q}{0.108mol}\\\\q=(-197.8kJ/mol\times 0.108mol)=-21.36kJ$

Hence, the amount of heat produced by the reaction is -21.36 kJ

3 0

3 years ago

An electron has an uncertainty in its position of 513 pm. What is the uncertainty in its velocity?

ella [17]

"The uncertainty in velocity is Δv=1.05⋅105m/s . According to the Heisenberg Uncertainty Principle, you cannot measure simultaneously with great precision both the momentum and the position of a particle. m - the mass of an electron - 9.10938⋅10−31kg."
-socratic.com

7 0

4 years ago