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alisha [4.7K]
2 years ago
13

Which of these tables represent a nonlinear function?

Mathematics
2 answers:
Nastasia [14]2 years ago
6 0
The third one. As the x increases by 1, the increase in y is not constant
ddd [48]2 years ago
3 0

Answer:

<u><em>(3)</em></u>

Step-by-step explanation:

Analise the slope m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

<em>(1).</em> (19-20)/(18-17) = - 1 ; (18-19)/(19-18) = - 1 ; (17-18)/(20-19) = - 1 ⇒ table represents a linear function.

<em>(2).</em> (-17+16)/(18-17) = - 1 ; (-18+17)/(19-18) = - 1 ⇒ table represents a linear function.

<em>(3).</em> (17-16)/(18-17) = <u><em>1</em></u> ; (19-17)/(19-18) = <u><em>2</em></u> ⇒ <em>table represents a nonlinear function.</em>

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The vertex of this parabola is at (-2, 5). Which of the following could be it’s equation? A. Y=3(x+2)^2-5 B. Y=3(x-2)^2-5 C. Y=3
Mariulka [41]

Answer:  C. y=3(x+2)^{2} +5


Step-by-step explanation:

1. You have the following equation of the parabola in Vertex form:

y=a(x-h)^{2}+k

Where h is the x-coordinate of the vextex and k is the y-coordinate of the vextex.

2. You know that the vertex of this parabola is at (-2, 5), then, susbtitute this point into the equation. Then, you obtain:

y=3(x+2)^{2}+5

3. Therefore, the answer is the option C.


5 0
3 years ago
Read 2 more answers
Kurt is flying his airplane over a campground. He spots a small fire below at an angle of depression of 32 degrees. If the horiz
Crank

Answer:

3293 ft to nearest tenth = side

Step-by-step explanation:

To find altitude this is the same in trigonometry as finding the side and we use calculation below in finding the hypotenuse which is same term as side for the angle of depression just to double check that height (altitude is less than slope in calculation).

sin (32) = 0.9271838546

3600/0.9271838546 = 3882.725074

= 3883 ft to nearest tenth. = slope

Then cos (32)x3882.725074 = 3292.737608

= 3293 ft to nearest tenth = side

7 0
3 years ago
An acute triangle had two sides measuring 8cm and 10 cm what is the best representation of the possible range of values for tge
katrin2010 [14]
The third side must be >2 and < 18

To test if a triangle is acute, right or obtuse:
1) Square all 3 sides
2) Sum the squares of the 2 shortest sides
3) Compare this sum to side 3 squared
if sum > side 3 squared it is an acute triangle
if sum = side 3 squared it is a right triangle
if sum < side 3 squared it is an obtuse triangle

The shortest side 2 can be is "less than 2" so we'll say it is 2.00000001
three sides squared =
<span> <span> <span> 4.00000004 </span> </span> </span>
64
100
Summing the 2 shortest sides 4.00000004 + 64 = <span>68.00000004
</span><span>68.00000004 is less than 100 so it is an obtuse triangle no matter how long the third side is.

</span>
8 0
3 years ago
What is the point slope equation of a line with slope -5 that contains the point (6,3)
ehidna [41]

Step-by-step explanation:

Given

Slope (m) = -5

Point

(x1 , y1) = ( 6 , 3)

So the equation is

y - y1 = m ( x - x1)

y - 3 = -5 ( x - 6)

y - 3 = -5x +30

5x + y = 30 + 3

5x + y = 33

5x + y - 33= 0

Which is the required equation.

Hope it will help you :)

3 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
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