These two angles are alternate interior, meaning that they are the same.
Therefore, 11x-10 = 2x+17
Solve to get x = 3; the two angles both equal to 23 degrees
and since EGF and DGE together form 90, DGE = 90-23 = 67
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Answer:
y = -3x^2 -9x +30
Step-by-step explanation:
When a polynomial has a zero at x=p, it has a factor of (x -p). The factors of your quadratic are ...
f(x) = (x +5)(x -2)
At the point x=3, the value of this product is ...
f(3) = (3 +5)(3 -2) = (8)(1) = 8
In order for that value to be -24, it needs to be multiplied by a scale factor of -3. The quadratic you want is ...
y = -3(x +5)(x -2)
y = -3x^2 -9x +30 . . . . . standard form
Answer:
No solutions
Explanation:
The given system of equations is
2y = x + 9
3x - 6y = -15
To solve the system, we first need to solve the first equation for x, so
2y = x + 9
2y - 9 = x + 9 - 9
2y - 9 = x
Then, replace x = 2y - 9 on the second equation
3x - 6y = -15
3(2y - 9) - 6y = -15
3(2y) + 3(-9) - 6y = -15
6y - 27 - 6y = -15
-27 = -15
Since -27 is not equal to -15, we get that this system of equation doesn't have solutions.
Answer:
d.
Step-by-step explanation:
i looked at the graph!
