The oxd state of O is -2
the oxidation state, of O2 is(-2)2
the oxd state of Se will be +4
the oxd state of compound will be zero
Answer:
Well they both would say numbers
Explanation:
The reason why is they both speak english
Conjugate base of Propanoic acid (
is propanoate where -COOH group gets converted to -CO
. The structure of conjugate base of Propanoic acid is shown in the diagram.
The 
above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.
= 
+ log![\frac{[Conjugate base]}{[acid]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BConjugate%20base%5D%7D%7B%5Bacid%5D%7D)
=4.9+log
=5.85
As 90% conjugate base is present, so propanoic acid present 10%.
Answer:
What make Boron Boron is that it has 5 protons, and will therefor have 5 electrons in the unionized state. While I was looking this up I learned that there are two stable isotopes, Boron 10 with five neutrons, and boron 11 with six. The more common is boron 11, which is 80.1% of naturally occuring boron.
