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solmaris [256]
3 years ago
9

What Happens when the temperature of an object increases?

Chemistry
2 answers:
Pepsi [2]3 years ago
6 0
D) The objects particles move closer together.
algol [13]3 years ago
5 0

a). the objects particles move faster .

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a major textile dye manufacutrer developed a new yellow dye. the dye has a percent composition of 75.95%C, 17.72%n and 6.33%H by
Delicious77 [7]

The molecular formula of dye:

A major textile dye manufacturer developed a new yellow dye with a molecular formula C_{15}N_{3}H_{15}.

Given:

Percentage composition:

C = 75.95%

N = 17.72%

H = 6.33%

Molar mass = 240 g

To find: molecular formula of dye

Calculation:

Let's assume the mass of the compound is 100 gm.

So,  Mass of C = 75.95 gm

Mass of N = 17.72 gm

Mass of H = 6.33 gm

The number of moles = given mass/mass

Therefore, the number of moles of C = 75.95/12 = 6.33

The number of moles of N = 17.72/14 = 1.27

Number of moles of H =6.33/1 = 6.33

Simplest ratio:

C = 6.33/1.27 = 4.98 =5

N = 1.27/1.27 = 1

H = 6.33/1.27 = 4.98 =5

Therefore, the empirical formula is C_{5}NH_{5}

The mass of empirical formula = 12 x 5 + 14 + 1 x 5 = 79 gm

Number of moles= molar mass/ empirical formula

n = 240/79 = 3.04 =3

Therefore, molecular formula = empirical formula x n

Hence, molecular formula = C_{15}N_{3}H_{15}

Learn more about molecular formulas here,

brainly.com/question/24083714

#SPJ4

6 0
2 years ago
Is glass breaking physical or a chemical
serg [7]

Answer:

<h2>physical </h2>

Explanation:

I hope this helps

3 0
3 years ago
Single covalent bond is preset in ---- <br>•NH3 <br>•NaCl <br>•KCl <br>•MgCl2 <br>•Other:___​
wariber [46]

Answer:

\:  \:  \:

•NH3(~ ̄³ ̄)~

3 0
3 years ago
What is the mass of 0.25 mol of sulfur atom
tatiyna

Answer:

8.0 g

Explanation:

To convert moles to grams, you need to use the molar mass.  The molar mass of sulfur is 32.06.  The molar mass is the atomic mass of the atom.

(0.25 mol) × (32.06 g/mol) = 8.015 g

Round for significant figures.

8.015 g ≈ 8.0 g

6 0
4 years ago
For the net reaction: 2AB + 2C → A2 + 2BC, the following slow first steps have been proposed. AB → A + B 2C + AB → AC + BC 2AB →
puteri [66]

This is an incomplete question, here is a complete question.

For the net reaction: 2AB + 2C → A2 + 2BC, the following slow first steps have been proposed.

(1) AB → A + B

(2) 2C + AB → AC + BC

(3) 2AB → A₂ + 2B

(4) C + AB → BC + A

What rate law is predicted by each of these steps?

Answer : The rate law expression for the following reactions are:

(1) \text{Rate}=k[AB]

(2) \text{Rate}=k[C]^2[AB]

(3) \text{Rate}=k[AB]^2

(4) \text{Rate}=k[C][AB]

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The general reaction is:

A+B\rightarrow C+D

The general rate law expression for the reaction is:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

R = rate  law

k = rate constant

[A] and [B] = concentration of A and B reactant

Now we have to determine the rate law for the given reaction.

(1) The balanced equations will be:

AB\rightarrow A+B

In this reaction, AB is the reactant.

The rate law expression for the reaction is:

\text{Rate}=k[AB]

(2) The balanced equations will be:

2C+AB\rightarrow AC+BC

In this reaction, C and AB are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[C]^2[AB]

(3) The balanced equations will be:

2AB\rightarrow A_2+2B

In this reaction, AB is the reactant.

The rate law expression for the reaction is:

\text{Rate}=k[AB]^2

(4) The balanced equations will be:

C+AB\rightarrow BC+A

In this reaction, C and AB are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[C][AB]

7 0
4 years ago
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