How many electrons must you add to Boron-10 to create a neutral atom? How many electrons must you add to Boron-11 to create a ne
1 answer:
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Answer:
The net energy is 2.196 eV
Explanation:
Basically, the energy of an atom increases when it absorbs a photon. In addition, the wavelength of the emitted photon is longer such that the atom absorbed a net energy in the process.
Using:
ΔE = h*c*(1/λ - 1/λ
)
where:
ΔE is the net energy in eV (electron-volt). 1 eV is equivalent to 1.602* J.
h = 4.135* eVs
c = 3* m/s
λ = 300 nm = 300*
m
λ = 640 nm = 640*
m
Thus:
ΔE = 4.135* eVs*3*
m/s*(
)
ΔE = 4.135**3*
*1.77*
eV = 2.196 eV
Answer:
Explanation:
Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.
The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.
- m= 1.85 kg
- g= 9.8 m/s²
- h= 2.23 m
Substitute the values into the formula.
Multiply the first 2 numbers together.
Multiply again.
- 1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
- Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J
The textbook has <u>40.4299 Joules of potential energy.</u>