1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
viktelen [127]
3 years ago
14

consider multiplying 26.2 by 16.43. what would a mathematician say the answer is? what would a scientist say the answer is?

Chemistry
1 answer:
levacccp [35]3 years ago
4 0

Answer:

Well they both would say numbers

Explanation:

The reason why is they both speak english

You might be interested in
Predict the mass of iron (III) sulfide produced when 3.0 g of iron filings react completely with 2.5 g of yellow sulfur solid, S
777dan777 [17]
1) Chemical equation

16Fe(s) + 3S8(s) ---> 8Fe2S3

2) Molar ratios:

16 mol Fe : 3 mole S8 : 8 mol Fe2S3

3) Convert masses in grams to number of moles

number of moles = mass in grams / molar mass

a) iron, Fe

mass = 3.0 g
atomic mass = 55.845 g/mol

=> number of moles of Fe = 3.0g / 55.845 g/mol = 0.0537 mol

b) Sulfur, S8

mass = 2.5 g
molar mass = 8*32.065 g/mol = 256.52 g/mol

=> number of moles of S8 = 2.5g / 256.52 g/mol = 0.009746 mol

4) Limiting reactant

Theoretical ratio                           actual ratio

16 mol Fe / 3 mol S8                 0.0537 mol Fe / 0.009746 mol S8

5.33                                               5.50

So, there is a little bit more Fe than the theoretical needed to react all the S8, which means the S8 is the limiting reactant.

5) Calculate the number of moles of iron (III) produced with 2.5 g (0.009746 moles) of S8

3moles S8 / 8 moles Fe2S3 = 0.009746 moles S8 / x

=> x = 0.009746 * 8 / 3 moles Fe2S3 = 0.026 moles Fe2S3

6) Convert 0.026 moles Fe2S3 into grams

mass in grams = number of moles * molar mass

molar mass of Fe2S3 = 207.9 g/mol

mass = 0.026 mol * 207.9 g/mol = 5.40 g

7) Answer: option D)




3 0
3 years ago
Read 2 more answers
All of the following are units for pressure except _____. A. Pa B. psi C. atm D. Hg
MA_775_DIABLO [31]

Answer:

B. psi

Explanation:

Pa is Pascal

atm is atmosphere

Hg is Mercury

hope it helps.

6 0
3 years ago
Experiment ideas I could win a lot of money from school
AleksAgata [21]

I am not all understood but for the school to earn money you can:

make  

--a raffle

--lotto

-- yard sale  

-- class photo  

-- origami for sale or something

-- buffet or food sale (example all Friday ice cream sale, 2 livre ice cream)

6 0
3 years ago
Question 5 of 10
OverLord2011 [107]

Answer:

4.2  g  

Explanation:

The VOLUME of the ring is   4.2 - 4.0 = .2 ml  = .2 cm^3

the MASS of the ring is this times the density

.2 cm^3  *  21 g/cm^3 = 4.2 g

4 0
2 years ago
Read 2 more answers
What is the mass of a neutron?<br><br> 1/2,000 amu<br> 1 amu<br> 2,000 amu<br> 1/200 amu
pashok25 [27]

Vas happenin!!



1 amu is the correct answer


Hope this helps


-Zayn Malik
8 0
3 years ago
Read 2 more answers
Other questions:
  • What does a Stationary object line look like?
    5·1 answer
  • Saccharin, a sugar substitute, is a weak acid with pka=2.32 at 25 ∘c. it ionizes in aqueous solution as follows: hnc7h4so3(aq)←−
    6·1 answer
  • There are two stable isotopes of bromine . their masses are 78.9183 amu and 80.9163 amu. if the average atomic mass of bromine i
    8·1 answer
  • How is salt water classified?
    9·1 answer
  • The half-life of potassium-40 is 1.3 billion years. If a rock that formed 2.6 billion years ago originally contained 5 grams of
    12·1 answer
  • Calculate moles of naoh 38.18ml of 0.550M
    6·1 answer
  • The number of electrons in an oxide ion O^2- is?
    7·1 answer
  • Pls answer 24 and 26.pls explain
    8·1 answer
  • Give me a time table of how to revise my exam syllabus within 1 month
    14·1 answer
  • In both trials, you started with the same amounts of nitrogen and oxygen atoms. In this situation, did the equilibrium amounts c
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!