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3 years ago

consider multiplying 26.2 by 16.43. what would a mathematician say the answer is? what would a scientist say the answer is?

Chemistry

1 answer:

levacccp [35]3 years ago

4 0

Answer:

Well they both would say numbers

Explanation:

The reason why is they both speak english

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The unbalanced equation for the reduction of copper(I) sulfide with oxygen is given below. What mass of copper is produced from

uranmaximum [27]

<u>Answer:</u> The mass of copper produced is 7.12 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of copper (I) sulfide = 8.80 g

Molar mass of copper (I) sulfide = 156.2 g/mol

Putting values in equation 1, we get:

$\text{Moles of copper (I) sulfide}=\frac{8.80g}{156.2g/mol}=0.056mol$

The chemical equation for the reaction of copper (I) sulfide and oxygen gas follows:

$Cu_2S+O_2\rightarrow 2Cu+SO_2$

By Stoichiometry of the reaction:

1 mole of copper (I) sulfide produces 2 moles of copper

So, 0.056 moles of copper (I) sulfide will produce = $\frac{2}{1}\times 0.056=0.112mol$ of copper

Now, calculating the mass of copper from equation 1, we get:

Molar mass of copper = 63.55 g/mol

Moles of copper = 0.112 moles

Putting values in equation 1, we get:

$0.112mol=\frac{\text{Mass of copper}{63.55g/mol}\\\\\text{Mass of copper}=(0.112mol\times 63.55g/mol)=7.12g$

Hence, the mass of copper produced is 7.12 grams

6 0

3 years ago

Several students want to conduct a descriptive investigation on igneous rocks. Which process is most likely to be part of their

iris [78.8K]

Answer:

Explanation:

They will collect samples from different sites and write their observations

8 0

3 years ago

Assuming a car (with a 70-L) gas tank can hold approximately 50,000 (5.00 * 10^4) g of octane(C8H18) or 50,000 (5.00 * 10^4) g o

konstantin123 [22]

Answer:

- From octane: $m_{CO_2}=1.54x10^5gCO_2$

- From ethanol: $m_{CO_2}=9.57x10^4gCO_2$

Explanation:

Hello,

At first, for the combustion of octane, the following chemical reaction is carried out:

$C_8H_{18}+\frac{25}{2} O_2\rightarrow 8CO_2+9H_2O$

Thus, the produced mass of carbon dioxide is:

$m_{CO_2}=5.00x10^4gC_8H_{18}*\frac{1molC_8H_{18}}{114gC_8H_{18}}*\frac{8molCO_2}{1molC_8H_{18}}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=1.54x10^5gCO_2$

Now, for ethanol:

$C_2H_6O+3O_2\rightarrow 2CO_2+3H_2O$

$m_{CO_2}=5.00x10^4gC_2H_6O*\frac{1molC_2H_6O}{46gC_2H_6O}*\frac{2molCO_2}{1molC_2H_6O}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=9.57x10^4gCO_2$

Best regards.

3 0

3 years ago

20 POINTS AND BRAINLIEST

maksim [4K]

Answer:

ceramic

Explanation:

7 0

2 years ago

Is 2OH−+Ca2+−>2Ca(OH)2 balanced

wariber [46]

Answer:

No.

Explanation:

No. There is 1 atom of Ca on the left and 2 Ca's on the right and 2 OH's on the left and 4 on the right.

The balanced equation is:

4OH- + 2Ca2+ ----> 2Ca(OH)2.

3 0

3 years ago

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