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Georgia [21]
3 years ago
5

can someone help me with this, i don’t understand, do we have to like name each shape ?? if so please help me!! please please pl

easee

Mathematics
1 answer:
ikadub [295]3 years ago
7 0

Answer: IT's asking for you to put the letter of the shapes next to they're name

Step-by-step explanation:

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Round the nearest hundredth. 53.789
hammer [34]

Answer: 53.79

Step-by-step explanation:

3 0
3 years ago
Given the set definitions below, find X Y. X = {100, 200} Y = {1,2}
Veseljchak [2.6K]
The Cartesian product of two sets can be defined as the following: the set of all possible pairs where the 1st coordinate is an element of the 1st set and the 2nd coordinate is the element of the 2nd set. This has an obvious generalization for n sets (the cartesian product has then n coordinates).
Let us pick now all the pairs that have 100 as their first coordinate. We then have 2 choices for the 2nd coordinate, 1 and 2. Hence, the 2 pairs are: (100,1), (100,2). Similarly, if 200 is the first coordinate, the pairs are (200,1), (200,2).
These 4 pairs are the cartesian product (we have 4 pairs =2 elements from X* 2 elements from Y) .
It helps to remember that the cartesian product has as many elements as the product of the number of elements of each set.
4 0
3 years ago
Jan had a bag of marbles. She gave half of them to James and then a third of the marbles still in the bag to pat. She then had 6
Firdavs [7]

Answer:

32 marbles

Step-by-step explanation:

Since she only has 6 left, you multiply it by 3 to get the amount she gave to Pat. Then you multiply that number by 2 to get the final amount.

6 0
3 years ago
If f(x) = x + 4 and g(x) = x^2-1, what is<br> (gºf)(x)?
aliina [53]

Answer:

x^2+8x+15

Step-by-step explanation:

f(x)=x+4 \\\\g(x)=x^2-1 \\\\(g\circ f)(x)=(x+4)^2-1=\\\\x^2+8x+16-1=\\\\x^2+8x+15

Hope this helps!

8 0
3 years ago
Read 2 more answers
What is 2 to the power of 4 over 3 equal to? (5 points)
ryzh [129]

Answer:

The answer is the option C

cube root of 16

Step-by-step explanation:

Remember that

a^{\frac{x}{y}} =\sqrt[y]{a^{x}}

in this problem we have

a^{\frac{x}{y}}=2^{\frac{4}{3}}

therefore

2^{\frac{4}{3}} =\sqrt[3]{2^{4}}=\sqrt[3]{16}

4 0
3 years ago
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