2 years ago

Estimating Areas and Areas of Circles

Mathematics

1 answer:

umka21 [38]2 years ago

3 0

Answer:

1)84 yd

2)63 in

3)7853.98 mm (round as you want)

4)153.94 ft

5)201.06 m

Step-by-step explanation:

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Algebra 1 A Adaptive CR (JL22) 1/Tools Of The Trade

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The simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$

Expressions raise to power 0 is 1.

So, we have:

$(4^3)(\frac{4^4x^4}{3^2x^2y^2})$

Apply the law of indices to expression with common base

$(\frac{4^{4+3}x^{4-2}}{3^2y^2})$

Evaluate the sum and difference

$(\frac{4^7x^2}{3^2y^2})$

Remove the bracket

$\frac{4^7x^2}{3^2y^2}$

Hence, the simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$

Read more about exponents at:

brainly.com/question/847241

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Is 3(x+x+y) equivalent to 3x+3(x+y)

mote1985 [20]

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Step-by-step explanation:

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3 years ago

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You are supposed to distribute to only one term (the first).

Tom [10]

Answer:

true

Step-by-step explanation:

There is no distribution (unless you count substitution) in the second set of terms.

Edit: I think I get what your question is now. You are supposed to distribute to every term inside the parenthesis (false)

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