When aqueous solutions of Potassium Carbonate and Copper Nitrate are mixed, the potassium will displace the copper, as it is more reactive, and Potassium Nitrate and Copper Carbonate will be formed.
The equation for this reaction is (ignoring state symbols):
K₂CO₃ + Cu(NO₃)₂ ⇒ 2KNO₃ + CuCO₃
A student tested a 0.1 M aqueous solution and made the
following observations conducts electricity, turns blue litmus to red and reacts
with Zn(s) to produce gas bubbles. The compound that could be the solute in
this solution is HBr. The answer is number 3.
Answer:
79.0 g
Explanation:
1. Gather the information in one place.
MM: 148.89 253.81
2NaI + Cl2 → I2 + 2NaCl
m/g: 67.3
2. Moles of I2
n = 67.3 g × (1 mol/253.81 g) = 0.2652 mol I2
2. Moles of NaI needed
From the balanced equation, the molar ratio is 2 mol NaI: 1 mol I2
n = 0.028 76 mol I2× (2 mol NaI/1 mol I2) = 0.5303 mol NaI
3. Mass of NaI
m = 0.5303 mol × (148.89 g/1 mol) = 79.0 g NaI
It takes 79.0 g of NaI to produce 67.3 g of I2.
If 5.60g of a gas at 2.50atm dissolves in 3.5-l of water.
this means you probably have to multiply 5.60g*2 because 2.50atm go into 5.00atm twice 5.60g(2)= 11.2
Answer:
yes they are broken down into smaller units
