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erma4kov [3.2K]
3 years ago
11

Pls help me 20 points ty

Chemistry
2 answers:
qaws [65]3 years ago
6 0

Answer:

what do you need help with i cant see it

Explanation:

belka [17]3 years ago
6 0

Answer:

See the image for answer.

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50 grams of water is placed into a beaker the mass of the beaker is now 115 grams what is the mass of the empty beaker
marissa [1.9K]
65 Grams is the mass of the beaker because you just take the mass   of Water + Beaker and take the water away now you have the mass of the beaker
6 0
3 years ago
Complete these equations for the ionization of an Arrhenius acid or base in water. Include the states of the products.
Mazyrski [523]
1)
 HI(aq) → H⁺(aq) + I⁻(aq)
So this is an Arrhenius acid because it releases H⁺.

2)
LiOH(s) → Li⁺ + OH⁻
So this is an Arrhenius base because it releases OH⁻
3 0
3 years ago
Zinc + Hydrochloric acid — Zinc chloride + Hydrogen [Zn +2 HCI → ZnCl2 + H2] is an
Jet001 [13]
Double replacement i believe
6 0
3 years ago
Explain how particles move before during and after melting
Aleksandr-060686 [28]

Answer:

Particles would move more freely, while still staying close together depending on the shape of the liquid

Explanation:

Melting is the process of going from a solid to a liquid due to the increase in heat/energy. This increase in heat/energy increases the speed at which the atoms within the object moves. Lets say we had an ice cube. While it is a cube, the particles inside the cube are slow and compact, staying close together.

When enough energy is gained, this makes the particles begin to move faster, gaining heat and energy which results in the ice cube melting and moving more freely than normal.

3 0
2 years ago
Read 2 more answers
How many moles of chlorine are used up in a reaction that produces 0.35kg of BCl3
maw [93]

4.48 mol Cl2. A reaction that produces 0.35 kg of BCl3 will use 4.48 mol of Cl2.

(a) The <em>balanced chemical equation </em>is

2B + 3Cl2 → 2BCl3

(b) Convert kilograms of BCl3 to moles of BCl3

MM: B = 10.81; Cl = 35.45; BCl3 = 117.16

Moles of BCl3 = 350 g BCl3 x (1 mol BCl3/117.16 g BCl3) = 2.987 mol BCl3

(c) Use the <em>molar ratio</em> of Cl2:BCl3 to calculate the moles of Cl2.

Moles of Cl2 = 2.987 mol BCl3 x (3 mol Cl2/2 mol BCl3) = 4.48 mol Cl2

4 0
3 years ago
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