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Leona [35]
3 years ago
8

PLEASE ANSWER THIS QUESTION Show that 4x – 7 is equivalent to 4(x - 1) – 3 when x = 3.​

Mathematics
1 answer:
Drupady [299]3 years ago
7 0

Answer:

4(3) - 7 = 4(3 - 1) - 3

12 - 7 = 4(2) - 3

5 = 8 - 3

= 5

They are equivalent because when they are both simplified they have the same answer 5

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AlgebraName1. If f(x) = 2x - 4, find each valdea)(3)b) f(x) = 9
rosijanka [135]

Answer:

Step-by-step explanation:

Comment

The question is since f(x) really means y, then when y = 9 what's x?

Solution

y = 2x - 4

y = 9

9 = 2x - 4                Add 4 to both sides

9+4 = 2x                 Combine

13 = 2x                    Divide both sides by 2

13/2 = 2x/2              

6.5 = x

Do you mean what is f(X) when x is 3. f(3) = 2x - 4. So what is y when x = 3

y = 2x - 4                   Substitute 3 for x

y = 2*3 - 4                  Combine

y = 6 - 4

y = 2

5 0
2 years ago
Help please as soon as possible
IRISSAK [1]

Answer:

5/3 divided by 1/3 is 5.

6 0
3 years ago
Read 2 more answers
Rick and two friends share a large bag of popcorn which cost $6.25 and a large soda which cost $3.25. They divide the cost evenl
romanna [79]
Add the prices together
Then divide by 3.

*6.25 + 3.25 = 9.50/3 = 2 of them pay 3.16 while the other pays 3.17.
7 0
3 years ago
Read 2 more answers
-5x - 16 + 3x = -23 - 9x<br><br> ???Anyone I need help
Veseljchak [2.6K]

Answer:

x=−1

Step-by-step explanation:

Let's solve your equation step-by-step.

−5x−16+3x=−23−9x

Step 1: Simplify both sides of the equation.

−5x−16+3x=−23−9x

−5x+−16+3x=−23+−9x

(−5x+3x)+(−16)=−9x−23(Combine Like Terms)

−2x+−16=−9x−23

−2x−16=−9x−23

Step 2: Add 9x to both sides.

−2x−16+9x=−9x−23+9x

7x−16=−23

Step 3: Add 16 to both sides.

7x−16+16=−23+16

7x=−7

Step 4: Divide both sides by 7.

7x

7

=

−7

7

x=−1

Answer:

x=−1

5 0
3 years ago
Read 2 more answers
The sum of the first and second of three consecutive even integers is 158. find the three even integers.
Evgesh-ka [11]
Teh three terms are 78, 80, and 82
7 0
4 years ago
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