Answer:
<em>Proof below</em>
Step-by-step explanation:
<u>Right Triangles</u>
In any right triangle, i.e., where one of its internal angles is 90°, some interesting relations stand. One of the most-used is Pythagora's Theorem.
In a right triangle with shorter sides a and b, and longest side c, called the hypotenuse, the following equation is satisfied:

The image provided in the question shows a line passing through points A(0,4) and B(3,0) that forms a right triangle with both axes.
The origin is marked as C(0,0) and the point M is the midpoint of the segment AB. We have to prove.

First, find the coordinates of the midpoint M(xm,ym):


Thus, the midpoint is M( 1.5 , 2 )
Calculate the distance CM:


CM=2.5
Now find the distance AB:

AB=5
AB/2=2.5
It's proven CM is half of AB
Answer:
Step-by-step explanation:
let the number=x
5+2x≤27
2x≤25-5
2x≤20
x≤4
we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>
We know that at 8:00 a.m. there were t inches of snow in the ground.
At 5:00 p.m. there were 3t inches of snow in the ground.
Then the difference between the heights of the snow is:
3t- t = 2t
And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:
3t = 12in
t = (12in)/3 = 4 in
Replacing that in the difference of heights:
2t = 2*4in = 8in
From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
The answer would be 16
11 + (8-3)^2 - 20 = 16
C your welcome have a nice day