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3 years ago

In a display at a museum, two planets have volumes of 8 cubic inches and 27 cubic

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

7 0

Answer:

2:3

Step-by-step explanation:

V = 4/3*pi*r^3

Diameter = 2r

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Please, I need an answer to this question urgently.

Blababa [14]

Answer:

156

Step-by-step explanation:

While solving we will have to use the area formula of the rectangle, which is :A=w*l ; length*width=A.

Steps:
1)let’s consider that the shape is a full rectangle. => 16*12=192.

2)9*2=18 -> 18*2=36

3)192-36=156.

4 0

2 years ago

Read 2 more answers

If 10% is deducted from bill, $58.50 remains to be paid. How much is original bill?

julsineya [31]

Answer:

$65.33

Step-by-step explanation:

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3 years ago

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Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Tems11 [23]

Answer and explanation:

To find : Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Solution :

The area of the square is given by,

$A=s^2$ where s is the side length.

We know, $1 \text{ hectare}=10,000\ m^2$

1) The area of square plot is 7 hectare.

Area in meter square is $A=7\times 10000=70000\ m^2$

Substitute the value in the formula,

$70000=s^2$

$\sqrt{70000}=s$

$264.57=s$

Side nearest to 1/10th meter is 264.8 meter.

2) The area of square plot is 12 hectare.

Area in meter square is $A=12\times 10000=120000\ m^2$

Substitute the value in the formula,

$120000=s^2$

$\sqrt{120000}=s$

$346.41=s$

Side nearest to 1/10th meter is 346.4 meter.

3) The area of square plot is 30 hectare.

Area in meter square is $A=30\times 10000=300000\ m^2$

Substitute the value in the formula,

$300000=s^2$

$\sqrt{300000}=s$

$547.72=s$

Side nearest to 1/10th meter is 547.7 meter.

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2 years ago

A function, f(x)=4x+5, has a domain 0<=x<=50. What is the range? How do you do this??

babunello [35]

Step-by-step explanation:

remember the domain is the interval or set of valid input (x) values. the range is the interval or set of the valid result (y) values.

so, the given domain tells us the interval to look at.

what are the functional values of the function between 0 and 50 ?

since the function is continuous (there are no gaps) in this interval, we can safely assume that all values between f(0) and f(50) are valid y values.

f(0) = 4×0 + 5 = 5

f(50) = 4×50 + 5 = 205

so, the range is 5 <= y <= 205

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2 years ago

Niech ktoś pomoże !<br> a)5 2\7 +1 3\7 -1\7=<br> b)4 5\9 -2 4\9 +3 2\9=<br> c)2 2\3 -(1 4\9 +2 3\9=

kvv77 [185]

A) 6 4/7

B) 5 3/9

C) 6 6/3

5 0

3 years ago