In the exercises 6-14, X=12, Y=10, Z=24. write each ratio in simplest form

1 answer:

7 0

X = 12, y = 10, z = 24

6. x to y : 12/10 reduces to 6/5...so simplest ratio is 6:5
7. z to x : 24/12 reduces to 2/1...so simplified ratio is 2:1
8. x + y to z : 22/24 reduces to 11/12...simplified ratio is 11:12
9. x/(x + z): 12/36 reduces to 1/3...simplified ratio is 1:3
10. (x + y)/(z + y) : 22/34 reduces to 11/17...simplified ratio is 11:17
11. (y-z)/(x-y) ; -14/2 reduces to -7/1...simplified ratio is -7:1
12. x:y:z : 12:10:24....simplified ratio is 6:5:12
13. z:x:y: 24:12:10..simplified ratio is 12:6:5
14. x:(x+y):(y+z) : 12:22:34...simplified ratio is 6:11:17

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A service center receives an average of 0.6 customer complaints per hour. Management's goal is to receive fewer than three compl

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Answer:

0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.

Step-by-step explanation:

We have the mean during a time-period, which means that the Poisson distribution is used to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

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$\mu$ is the mean in the given interval.

A service center receives an average of 0.6 customer complaints per hour.

This means that $\mu = 0.6h$ , in which h is the number of hours.

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8 hours means that $h = 8, \mu = 0.6(8) = 4.8$ .

The probability is P(X = 4).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 4) = \frac{e^{-4.8}*4.8^{4}}{(4)!} = 0.18203$

0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.

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Normal Distribution

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It is also called Gaussian distribution. The point near the peak is where most of the observations cluster, while the values further away from the mean will be distributed equally in both directions on the curve.