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3 years ago

Why is amniocentesis a more widely used test than cvs?

1 answer:

4 0

Higher probability of loss. Chorionic villus sampling (CVS) and Amniocentesis (AC). The prenatal diagnosis technique can be done earlier in fetal development CVS (first trimester --> 10-13 weeks). AC (second trimester --> 16-20 weeks)

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2 Which best describes an acid?

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D. A sour liquid that forms gas bubblee when mixed with copper

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The glow stick of a fluorescent light bulb or neon sign is caused by which state of matter?

lbvjy [14]

I believe it is B, liquid

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Read 2 more answers

Listed in the item bank are key terms expressions each of which is associated with one of the columns. Some terms may disable ad

11Alexandr11 [23.1K]

Answer:

The correct answer is -

Prokaryotic unicellular -

Eubacteria - is the domain of unicellular organisms that has a prokaryotic cell

Archaebacteria - is one of the two domains of the prokaryotic organisms that are unicellular.

Eukaryotic multicellular (autotroph) -

Plantae - is the multicellular kingdom of the eukaryotic cells and as they produce their own food by photosynthesis called autotrophs.

protists - the autotrophic protists that are multicellular comes under algae, especially red algae.

Eukaryotic multicellular (heterotroph) -

Animalia - The Animalia kingdom is the kingdom of the heterotrophic eukaryotic organism that mostly has multicellular bodies. They depend on plants or other animals for their food.

Fungi - are mostly heterotrophic eukaryotic as they get their nutrient from other organisms are mostly multicellular.

Protist - some protists are heterotrophic as well.

Eukaryotic multicellular/unicellular (heterotroph/autotroph) -

Plantae

protists

Animalia

Fungi

5 0

3 years ago

PLEASEEEE HELP MEEE

Nookie1986 [14]

The answer is i don’t know because i’m just doing this for points sorry!!! hope this helps

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3 years ago

The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. A 1.751 g sample of e

fredd [130]

Answer: The empirical formula for the given compound is $C_{4}H_{10}O$

Explanation:

The chemical equation for the combustion of ether follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=4.159g$

Mass of $H_2O=2.128g$

Mass of sample = 1.751 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 4.159 g of carbon dioxide, $\frac{12}{44}\times 4.159=1.134g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 2.128 g of water, $\frac{2}{18}\times 2.128=0.236g$ of hydrogen will be contained.

Mass of oxygen in the compound = (1.751) - (1.134 + 0.236) = 0.381 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.134g}{12g/mole}=0.0945moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.236g}{1g/mole}=0.236moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.381g}{16g/mole}=0.0238moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0238 moles.

For Carbon = $\frac{0.0945}{0.0238}=3.97\approx 4$

For Hydrogen = $\frac{0.236}{0.0238}=9.91\approx 10$

For Oxygen = $\frac{0.0238}{0.0238}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 10 : 1

Hence, the empirical formula for the given compound is $C_{4}H_{10}O$

7 0

3 years ago