(a) 841 lb/in; (b) 89.36 cm
(a) 1220 lb/1.45 in = 841 lb/in
(b) To quadruple a measurement is to <em>multiply it by 4</em>.
∴ 4 × 22.34 cm = 89.36 cm
The two carbon-sequestering methods that could reduce the impact of deforestation are afforestation and agriculture.
Carbon sequestering
- It is a process of capturing and storing the carbon dioxide gas of an atmosphere on a large scale.
- This is done to prevent adverse global climatic conditions
- The methods which can reduce the impact of deforestation are afforestation, wetlands, fertilizing ocean surfaces, agriculture, etc.
Afforestation
- Planting trees in the nonforest region or planting trees in the deforested region.
- By this more and more carbon dioxide gas will be absorbed by the tress from the atmosphere via photosynthesis and that will get involve in the carbon cycle.
- Help in re-establishing an ecosystem in the region and prevent soil erosion.
Agriculture
- Growing and planting crops which maintain carbon level of the soil, And along with absorbs carbon dioxide gas from the atmosphere.
- Will increase the concentration of oxygen gas in the atmosphere leading to prevent air pollution.
Learn more about carbon sequestering here:
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Answer:
Dark Matter
Explanation:
90 percent of the mass in the universe is dark matter
Ionic compound is a chemical compound composed of ions held together by electrostatic forces termed ionic bonding
Answer : The standard enthalpy of formation of ethylene is, 52.4 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The formation reaction of 
will be,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
(3) 
Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equation, we get :
(1) 
(2) 
(3) 
The expression for enthalpy of formation of will be,
Therefore, the standard enthalpy of formation of ethylene is, 52.4 kJ
