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2 years ago

40.8-10 to the power of 2

Mathematics

2 answers:

mash [69]2 years ago

7 0

948.64

Subtract then multiply by itself

No offense but can't you use a calculator?

EleoNora [17]2 years ago

5 0

Answer:

-4

Step-by-step explanation:

8-10 = -2

-2^2 = -4

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How do i simplify this problem?<br><br>12r+5s-7T+9s-4r

Nimfa-mama [501]

Answer: To simplify this problem you combine the like terms in the equation (numbers with the same variables.)

Demo: 12r + -4r = 8r

4 0

3 years ago

Read 2 more answers

All of the following are irrational except _____.

a_sh-v [17]

The number that is not irrational is $1.\overline{45}$ . The correct option is the second option $1.\overline{45}$

<h3>Irrational numbers </h3>

From the question, we are to determine which of the given options is not irrational

Irrational numbers are the set of real numbers that cannot be expressed in the form of a fraction, p/q, where p and q are integers.

$1.\overline{45}$ is a repeating decimal and it can be expressed as a fraction

$1.\overline{45} = \frac{144}{99}$

∴ $1.\overline{45}$ is not an irrational number. It is a rational number

The other options cannot the expressed as a fraction.

Hence, the number that is not irrational is $1.\overline{45}$ . The correct option is the second option $1.\overline{45}$

Learn more on Irrational numbers here: brainly.com/question/11919233

#SPJ1

5 0

1 year ago

Please answer! It would be appreciated if work is also shown!

borishaifa [10]

Quantity of paint left = $\frac{389}{480}$ gallons

Solution:

Quantity of yellow paint = $1\frac{1}{5}=\frac{6}{5}$ gallons

Quantity of green paint = $1\frac{1}{6}=\frac{7}{6}$ gallons

Quantity of blue paint = $\frac{7}{8}$ gallons

Quantity of paint used = $\frac{3}{4}$ gallons of each paint

Quantity of paint left = $1-\frac{3}{4}=\frac{1}{4}$ gallons of each paint

Quantity of paint left = $(\frac{6}{5}+\frac{7}{6}+\frac{7}{8})\times\frac{1}{4}$

Taking LCM for 5, 6, 8, we get LCM = 120

$(\frac{6}{5}+\frac{7}{6}+\frac{7}{8})\times\frac{1}{4}=(\frac{144}{120}+\frac{140}{120}+\frac{105}{120})\times\frac{1}{4}$

$=(\frac{389}{120})\times\frac{1}{4}$

$=\frac{389}{480}$

Hence, Mark will have $\frac{389}{480}$ gallons of paint left after painting the mural.

3 0

2 years ago

The ice cream parlor serves spherical scoops of ice cream with a radius of 1 in. What is the approximate volume of 2 scoops of i

Varvara68 [4.7K]

Answer: 8.37 in³

Step-by-step explanation:

Given the following :

Shape of icre cream scoop = sphere

Radius (r) = 1 inch

Volume of a scoop of icecream = volume of sphere :

4/3πr³

(4/3) × 3.14 × 1³

1.333 × 3.14 × 1

= 4.1867 in³

Hence, the volume of 2 scoops of ice cream will be :

2 × ( volume of a scoop of ice cream)

(2 × 4.1867) in³

= 8.37 in³

6 0

2 years ago

A tobacco company claims that its best-selling cigarettes contain at most 40 mg of nicotine. The average nicotine content from a

tatuchka [14]

Answer:

$t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722$

$df=n-1=15-1=14$

$p_v =P(t_{(14)}>2.722)=0.0083$

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

$\bar X=42.6$ represent the average nicotine content

$s=3.7$ represent the sample standard deviation

$n=15$ sample size

$\mu_o =40$ represent the value to check

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:

Null hypothesis: $\mu \leq 40$

Alternative hypothesis: $\mu > 40$

The statistic for this case would be:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replcing we got:

$t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722$

The degrees of freedom are:

$df=n-1=15-1=14$

The p value would be:

$p_v =P(t_{(14)}>2.722)=0.0083$

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

6 0

3 years ago