MgSO₄ + Pb(NO₃)₂ = PbSO₄(s) + Mg(NO₃)₂
Mg²⁺ + SO₄²⁻ + Pb²⁺ + 2NO₃⁻ = PbSO₄ + Mg²⁺ 2NO₃⁻
Pb²⁺ + SO₄²⁻ = PbSO₄
Answer:
2,347.8 grams
Explanation:
The freezing point depression Kf of water = 1.86° C / molal.
To still freeze at -12° C, then the molality of the solution 12/ 1.86 = 6.45 moles
The molecular weight of sorbitol (C6H14O6)is:
6 C = 6 ×12 = 72
14 H = 14 × 1 = 14
6 O = 6 × 16 = 96
...giving a total of 182
So one mole of sorbitol has a mass of 182 grams.
Since there are 2 kg of water, 2 × 6.45 moles = 12.9 moles can be added to the water to get the 12° C freezing point depression.
Therefore
grams = moles × molar mass
12.9 moles × 182 grams / mole = 2,347.8 grams of sorbitol can be added and still freeze
Try d)kinetic energy, if wrong sorry
Answer:
a 17 bc it is how it works
Answer:
B
Explanation:
All the properties listed above is for carbon ii oxide.
It is odorless, colorless and poisonous
It is formed from the incomplete combustion of fossil fuels
And it can actually interfere with the blood’s ability to carry oxygen
