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NeX [460]
2 years ago
13

Meyer used 8 loads of gravel to cover 2/5 of his driveway. How many loads of gravel will he need to cover his entire driveway?

Mathematics
1 answer:
stich3 [128]2 years ago
3 0

Answer:Meyer uses 2.5 loads

Step-by-step explanation:Why does he use 2.5? Because, he has 8 loads and with 1 load he covers 2/5 of his driveway so 2 loads covers 4/5 and 2.5 loads cover 5/5 of his driveway

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a model of an apartment is shown 1\4 in. represents 3 feet in the actual apartment. Find the actual area of the master bedroom
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Answer:12 feet by 9 feet


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1/4 = 3 feet, so every 1/4 of an inch there is three feet, e.g. 3/4 inches of that scale is 9 feet, 1 1/2 inches would be 18 feet, make sense?

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3 years ago
I need help ASAP) i need both answers (person who gets it right gets a brainlist and 5 stars)
Flauer [41]

Answer:

Part A: 24 meters

Part B: 33 meters²

Step-by-step explanation:

Part A: We know the length of 4 of the sides. The other two sides are 2 m & 1 m. Now add all of those values up. 3 + 7 + 5 + 6 + 2 + 1 = 10 + 11 + 3 = 21 + 3 = 24 meters. The perimeter of the polygon is 24 meters.

Part B: I'll split this into two rectangles: one is 3 by 7, and the other is 6 by 2. (3 * 7) + (6 * 2) = 21 + 12 = 33 meters². The area of the polygon is 33 meters².

8 0
2 years ago
Solve each triangle. Round your answers to the nearest tenth.<br>show work If possible ​
kvasek [131]
<h2>Answer:</h2>

∠ABC = 76°

BC = 20.1

CA = 28.0

<h2>Step-by-step explanation:</h2>

Solving the triangle means finding all unknown angles and sides of the triangle.

(i) Two of the angles (∠BCA = 60° and ∠CAB  = 44°) are given. To find the third angle (∠ABC), use one of the theorems stating <em>that the sum of angles of a triangle is equal to 180°.</em>

Therefore, the sum of angles of the triangle ABC is 180°. i.e

∠ABC + ∠BCA + ∠CAB = 180°

=> ∠ABC + 60° + 44° = 180°

=> ∠ABC + 104° = 180°

=> ∠ABC = 180° - 104°

=> ∠ABC = 76°

(ii) One side (BA) of the triangle is given. To get the other sides, we use the sine rule as follows;

=> \frac{sin60}{25} = \frac{sin44}{BC} = \frac{sin76}{CA}

=> \frac{sinBCA}{BA} = \frac{sinCAB}{BC} = \frac{sinABC}{CA}

<em>Substitute the necessary values</em>

\frac{sin60}{25} = \frac{sin44}{BC} = \frac{sin76}{CA}      ---------------------(ii)

(a) To get side BC, use the first two terms of equation (ii)

\frac{sin60}{25} = \frac{sin44}{BC}

<em>Cross multiply</em>

BC x sin 60 = 25 x sin 44

BC x 0.8660 = 25 x 0.6947

0.8660 x BC = 17.3675

BC = \frac{17.3675}{0.8660}

BC = 20.05

=> BC = 20.1 to the nearest tenth

(b) To get CA, use any two terms of equation (ii). Using the first and third terms, we have;

\frac{sin60}{25} = \frac{sin76}{CA}

<em>Cross multiply</em>

CA x sin 60 = 25 x sin 76

CA x 0.8660 = 25 x 0.9703

0.8660 x CA = 24.2575

CA = \frac{24.2575}{0.8660}

CA = 28.01

=> CA = 28.0 to the nearest tenth

5 0
3 years ago
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