Ummm because it need space to move around and function
Since isotopes of any given element all contain the same number of protons,
Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.
<h3>
Conservation of Linear Momentum</h3>
It states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.
Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.
The given parameters are;
The formula to find the speed will be
M1U1 - M2U2 = (M1 + M2)V
7500 × 5 - 1500 × 10 = (7500 + 1500)V
37500 - 15000 = 9000V
22500 = 9000V
V = 22500/9000
V = 2.5 m/s
Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.
Learn more about Collision here: brainly.com/question/7694106
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Answer:
Average Velocity = - 1.22 cm/s = - 0.0122 m/s
Explanation:
The average velocity of an object is defined as the ratio of the total distance traveled by the object to the total time taken by the object to cover the distance. Therefore, the average velocity of an object can be found by the following formula:
Average Velocity = Total Distance Covered/Total Time Taken
Average Velocity = (Final Position - Initial Position)/Total Time Taken
Average Velocity = (3.7 cm - 6.5 cm)/(2.3 s)
Average Velocity = (- 2.8 cm)/(2.3 s)
<u>Average Velocity = - 1.22 cm/s = - 0.0122 m/s</u>
here, the negative sign indicates the direction of the velocity or the movement of the object is leftwards or towards the origin approaching from right.
Answer:
a) x = 1.5 *10⁻⁴cos(524πt) m
b) v = -1.5 *10⁻⁴(524π)sin(524πt) m/s
a = -1.5 *10⁻⁴(524π)²cos(524πt) m/s²
c) x(1) = 1.5 *10⁻⁴ m = 1.5 *10⁻1 mm
x(0.001) = -1.13*10⁻⁵ m = -1.13*10⁻² mm
Explanation:
x = Acos(ωt)
ω = 2πf = 2π(262) = 524π rad/s
x = 1.5 *10⁻⁴cos(524πt)
v = y' = -Aωsin(ωt)
v = -1.5 *10⁻⁴(524π)sin(524πt)
a = v' = -Aω²cos(ωt)
a = -1.5 *10⁻⁴(524π)²cos(524πt)
not sure about the last part as time is generally not given in mm
I will show at 1 second and at 0.001 s to try to cover bases
x(1) = 1.5 *10⁻⁴cos(524π(1))
x(1) = 1.5 *10⁻⁴cos(524π)
x(1) = 1.5 *10⁻⁴(1)
x(1) = 1.5 *10⁻⁴ m = 1.5 *10⁻1 mm
x(0.001) = 1.5 *10⁻⁴cos(524π(0.001))
x(0.001) = 1.5 *10⁻⁴cos(0.524π)
x(0.001) = 1.5 *10⁻⁴(-0.0753268)
x(0.001) = -1.129902...*10⁻⁵ m
x(0.001) = -1.13*10⁻⁵ m = -1.13*10⁻² mm
