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1 year ago

A 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving

1 answer:

5 0

Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.

<h3>Conservation of Linear Momentum</h3>

It states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.

Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.

The given parameters are;

M1 = 7500 kg

U1 = 5 m/s

M2 = 1500

U2 = 20 sin 30 = 10 m/s

V = ?

The formula to find the speed will be

M1U1 - M2U2 = (M1 + M2)V

7500 × 5 - 1500 × 10 = (7500 + 1500)V

37500 - 15000 = 9000V

22500 = 9000V

V = 22500/9000

V = 2.5 m/s

Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.

Learn more about Collision here: brainly.com/question/7694106

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Substances which naturally attract each other called what

grandymaker [24]

Answer:

Ferromagnetism, physical phenomenon in which certain electrically uncharged materials strongly attract others. Two materials found in nature, lodestone (or magnetite, an oxide of iron, Fe3O4) and iron, have the ability to acquire such attractive powers, and they are often called natural ferromagnets.

Hope this help :)

5 0

3 years ago

A 80 W light bulb (normally run at 120 V) is attached to a transformer. The voltage source in the transformer is 65 V and Np = 3

Marina CMI [18]

67.8 turns needed by the secondary coil to run the bulb.

<u>Explanation</u>:

We know that,

$\text { Electric power }(p)=\frac{V^{2}}{R}$

$\text { Hence, } \frac{P_{1}}{P_{2}}=\frac{V_{1}^{2} / R}{V_{2}^{2} / R}$

$\frac{P_{1}}{P_{2}}=\frac{V_{1}^{2}}{V_{2}^{2}}$

For calculating number of turns

$\frac{N_{P}}{N_{S}}=\frac{V_{P}}{V_{S}}$

Given that,

$80 \mathrm{W}\left(P_{1}\right) \text { bulb with voltage } 120 \mathrm{V}\left(V_{1}\right) \text { is connected to a transformer. }$

$\text { The source voltage of a transformer is }\left(V_{P}\right) \text { is } 65 \mathrm{V}$

$\text { The number of turns in primary winding of transformer is }\left(N_{P}\right) \text { is } 30 .$

We need to find the number of turns in the secondary winding $\left(N_{S}\right)$ to run the bulb at 120W $\left(P_{2}\right)$

Firstly find the secondary voltage in the transformer use, $\frac{P_{1}}{P_{2}}=\frac{V_{1}^{2}}{V_{2}^{2}}$

$\frac{80}{120}=\frac{120^{2}}{V_{2}^{2}}$

$V_{2}^{2}=\frac{120^{2} \times 120}{80}$

$V_{2}^{2}=\frac{1728000}{80}$

$V_{2}^{2}=21600$

$V_{2}=\sqrt{21600}$

$V_{2}=146.9 \mathrm{V}=V_{S}$

Now, finding the number of turns in secondary coil. Use, $\frac{N_{P}}{N_{S}}=\frac{V_{P}}{V_{S}}$

$\frac{30}{N_{S}}=\frac{65}{146.9}$

$N_{S}=\frac{30 \times 146.9}{65}$

$N_{S}=\frac{4407}{65}$ $N_{S}=67.8$

The number of turns in the secondary winding are 67.8 turns.

6 0

3 years ago

One day you are driving your friends around town and you drive quickly around a corner without slowing down. You are going at a

Novay_Z [31]

Answer:

1.60 g

Explanation:

From the attached file below:

we can deduce that:

$v = v_x =v_y = 20 \ m/s \\t = 2s$

The distance traveled by 2 s will be:

x = vt

x = 20 m/s × 2 s

x = 40 m

The length is quarter of the circle with radius r,

so; if 2 πr = 4 x

Then radius (r) will be:

$r = \frac{4x}{2 \pi}\\\\r = \frac{4*40}{2 \pi}$

r = 25.5 m

The centripetal acceleration can be expressed as:

$a = \frac{v^2}{r}$

so;

$a = \frac{(20 \ m/s^2)}{25.5 \ m}$

a = 15.7 m/s²

the magnitude of the acceleration experienced by your unfortunate passengers in terms of acceleration due to gravity is then determined by the equation:

$a' = \frac{a}{g} g$

$a' = \frac{15.7 \m/s ^2}{9.81 \ m/s^2}\ g$

$a' = 1.60 \ g$

∴ The magnitude of the acceleration experienced by your unfortunate passengers during the turn = 1.60 g

6 0

4 years ago

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calculate the temperature at which the reading on Fahrenheit scale is equal to half the reading of Celsius scale

RideAnS [48]

Answer:

Therefore, the temperature at which the Fahrenheit scale reading is equal to half of the Celsius scale is −24.6∘C .

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3 years ago

Describe the procedures to change the phase of one of the substances. (What must you increase or decrease to change the phases?)

posledela

Answer:

Substances can change phase — often because of a temperature change. At low temperatures, most substances are solid; as the temperature increases, they become liquid; at higher temperatures still, they become gaseous.

Explanation:

7 0

2 years ago