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xeze [42]
10 months ago
8

A 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving

Physics
1 answer:
julia-pushkina [17]10 months ago
5 0

Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.

<h3>Conservation of Linear Momentum</h3>

It states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.

Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.

The given parameters are;

  • M1 = 7500 kg
  • U1 = 5 m/s
  • M2 = 1500
  • U2 = 20 sin 30 = 10 m/s
  • V = ?

The formula to find the speed will be

M1U1 - M2U2 = (M1 + M2)V

7500 × 5 - 1500 × 10 = (7500 + 1500)V

37500 - 15000 = 9000V

22500 = 9000V

V = 22500/9000

V = 2.5 m/s

Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.

Learn more about Collision here: brainly.com/question/7694106

#SPJ1

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8 0
3 years ago
Two charges, each q, are separated by a distance r, and exert mutual attractive forces of F on each other. If both charges becom
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Answer:

F = ⅔ F₀

Explanation:

For this exercise we use Coulomb's law

         F = k q₁q₂ / r²

let's use the subscript "o" for the initial conditions

          F₀ = k q² / r²

now the charge changes q₁ = q₂ = 2q and the new distance is r = 3 r

       

we substitute

          F = k 4q² / 9 r²

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3 0
3 years ago
A 18-g paper clip is attached to the rim of a phonograph record with a diameter of 48 cm, spinning at 3.2 rad/s. What is the mag
Artist 52 [7]

Answer:

Magnitude of its angular momentum = 0.0017 kgm²/s

Explanation:

Angular momentum, L = Iω

I is mass moment of inertia and ω is angular velocity.

Phonograph is in disc shape,

\texttt{I for disc =}\frac{MR^2}{2}

Radius = 0.5 x 48 = 24 cm = 0.24 m

Angular velocity, ω = 3.2 rad/s

Mass, M = 18 g = 0.018 kg

Substituting

     L=\frac{0.018\times 0.24^2}{2}\times 3.2 =0.0017kgm^2/s

Magnitude of its angular momentum = 0.0017 kgm²/s

5 0
2 years ago
If a horse is running at a speed of 35 m/s when it's rider pulls up on the reigns. After 5 seconds the horse slows down to a pac
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The answer is simply 5.51
7 0
3 years ago
Read 2 more answers
Bob is standing at rest. Wendy runs past him at a constant speed of 3.00 m/s. At the instant that Wendy passes him, Bob starts t
77julia77 [94]

Answer:

90 meters

Explanation:

To find the distance in which Bob catches up with Wendy, you first write down the motion equations of both Bob and Wendy.

Wendy has a constant speed, then you have:

x_1=v_1t           (1)

Bob has an accelerated motion, then, his equation of motion is:

x_2=v_2t+\frac{1}{2}at^2          (2)

v1: constant speed of Wendy = 3.00 m/s

v2: initial speed of Bob = 0 m/s

a: acceleration of Bob = 0.200m/s^2

When Bob catches up with Wendy x1 = x2, then you equal both equations and solve for time t:

x_1=x_2\\\\v_1t=\frac{1}{2}at^2\\\\t=\frac{2v_1}{a}

you replace the values of a and v1:

t=\frac{2(3.00m/s)}{0.200m/s^2}=30 s

Finally, you replace this value of time either the equation for x1 or the equation for x2, and you calculate the distance:

x_2=x_1=(3.00m/s)(30s)=90m

hence, Bob catches up with Wendy for a distance of 90m

3 0
3 years ago
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