The reactance of an inductor is given by:
X = 2πfL
X is the inductor's reactance
f is the frequency of the supplied voltage
L is the inductor's inductance
The given values are:
f = 60.0Hz
L = 43.8mH (I'm assuming the value is given in milli Henries because this is within the normal range of inductors)
Plug these values in and solve for X:
X = 2π(60.0)(43.8×10⁻³)
X = 16.512Ω
Round this value to 3 significant figures:
X = 16.5Ω
The relationship between AC voltage and current is given by:
V = IZ
V is the voltage
I is the current
Z is the impedance
For an AC inductor circuit, Z = X = 16.512Ω and V is the rms voltage 120V. Plug these values in to get the rms current:
120 = I×16.512
I = 7.2673A
Round this value to 3 significant figures:
I = 7.27A
Answer:
The electric field points to the left because the force on a negative charge is opposite to the direction of the field.
Explanation:
In an electric field, a positive charge has tendency to move from high to low potential and hence experience the electric force in the direction of electric field since electric field lines are directed from high to low potential.
In an electric field, a negative charge has tendency to move from low to high potential and hence experience the electric force in the direction opposite to electric field since electric field lines are directed from high to low potential.This phenomenon happened because The electric field from a positive charge will points away from the charge while the electric field from a negative charge will points toward the charge.
A non-contact force is a force which acts on an object without coming physically in contact with it. In contrast a contact force is a force which acts on an object coming physically in contact with it. ...
It tells us the number of protons in the nucleus of each atom of that element.
Answer:F=11.76 kN
Explanation:
Given
mass of rocket ![m=400 kg](https://tex.z-dn.net/?f=m%3D400%20kg)
Force F is applied up to a height of 100 m then it is shut off
final velocity v up to which force is applied is given by
![v^2-u^2=2 as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2%20as%20)
![v^2-0=2\times a\times 100](https://tex.z-dn.net/?f=v%5E2-0%3D2%5Ctimes%20a%5Ctimes%20100)
![v=\sqrt{200 a}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B200%20a%7D)
After this rocket continues to move to a maximum height under the action of gravity
using
![v_1^2-v^2=2 gs_2](https://tex.z-dn.net/?f=v_1%5E2-v%5E2%3D2%20gs_2)
![s_2=400-100=300 m](https://tex.z-dn.net/?f=s_2%3D400-100%3D300%20m)
![0-200 a=-2\times 9.8\times 300](https://tex.z-dn.net/?f=0-200%20a%3D-2%5Ctimes%209.8%5Ctimes%20300)
![a=3 g=3\times 9.8=29.4 m/s^2](https://tex.z-dn.net/?f=a%3D3%20g%3D3%5Ctimes%209.8%3D29.4%20m%2Fs%5E2)
thus Force is ![F=ma](https://tex.z-dn.net/?f=F%3Dma)
![F=400\times 29.4=11,760=11.76 kN](https://tex.z-dn.net/?f=F%3D400%5Ctimes%2029.4%3D11%2C760%3D11.76%20kN)