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xeze [42]
1 year ago
8

A 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving

Physics
1 answer:
julia-pushkina [17]1 year ago
5 0

Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.

<h3>Conservation of Linear Momentum</h3>

It states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.

Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.

The given parameters are;

  • M1 = 7500 kg
  • U1 = 5 m/s
  • M2 = 1500
  • U2 = 20 sin 30 = 10 m/s
  • V = ?

The formula to find the speed will be

M1U1 - M2U2 = (M1 + M2)V

7500 × 5 - 1500 × 10 = (7500 + 1500)V

37500 - 15000 = 9000V

22500 = 9000V

V = 22500/9000

V = 2.5 m/s

Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.

Learn more about Collision here: brainly.com/question/7694106

#SPJ1

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