Question

A 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving

Answer 1

Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.

Conservation of Linear Momentum

It states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.

Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.

The given parameters are;

• M1 = 7500 kg

• U1 = 5 m/s

• M2 = 1500

• U2 = 20 sin 30 = 10 m/s

• V = ?

The formula to find the speed will be

M1U1 - M2U2 = (M1 + M2)V

7500 × 5 - 1500 × 10 = (7500 + 1500)V

37500 - 15000 = 9000V

22500 = 9000V

V = 22500/9000

V = 2.5 m/s

Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.

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