There should be 6 per number
ex.
1234
1243
1342
1324
1432
1423
Answer:
t3 = 8, t5 = 14
Step-by-step explanation:
t3 = 2 + (3-1) × 3
t3 = 2 + (2) × 3
t3 = 2 + 6
t3 = 8
t5 = 2 + (5-1) × 3
t5 = 2 + (4) × 3
t5 = 2 + 12
t5 = 14
Answer:
{-3, -1, 1}
Step-by-step explanation:
Zeros refer to x-intercepts. X-intercepts are x values when y = 0. You can tell where they are by looking at where the line passes the x-axis.
Therefore, {-3, -1, 1} are the zeros.
Hello here is a solution :
x²-8y-6x+y²=4....(1)
A)
x²-6x = x²-2(3)x+9-9
= x²-2(3)x+3²-9
x²-6x =(x-3)² -9
B)
y²-8y = y²-2(4)y +4²-16
y²-8y = (y-4)²-16
C)
in (1) :
(x-3)² -9 +(y-4)²-16 = 4
(x-3)² +(y-4)² = 29 ...<span>is the standard form of the equation
</span> <span>Select answer 1 :
</span><span>A: 3
B: 4
C: (x−3)2+(y−4)2=29</span>
