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kow [346]
3 years ago
9

Assuming the pattern continues, what are the next two terms in this

Mathematics
1 answer:
pshichka [43]3 years ago
4 0
D. 53, 107
The pattern is multiplying the previous number by two and then adding one to it.
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If the volume of the pyramid is 72cm^3 what is the height
irakobra [83]

the height of the pyramid is 6cm

8 0
3 years ago
Please help me find the area of this irregular shape.
ANTONII [103]

Answer:

23 Cm(2)

Step-by-step explanation:

Sincerest Apologies if it is incorrect

if it's not 23 it may be:

26 Cm(2)

6 0
2 years ago
1/4×3/2×8/9 What is the Simplified fraction?
VARVARA [1.3K]

Answer:

1/3

Step-by-step explanation:

1/4×3/2×8/9

Rewriting

8/4 * 3/9 *1/2

Simplify

2 * 1/3 * 1/2

Rewriting

2/2 * 1/3

1 * 1/3

1/3

8 0
3 years ago
Read 2 more answers
A drum full of rice weighs 241/6 kg. If the empty drum weighs 55/4 kg, find the weight of rice in the drum.
gregori [183]
Let x be rice weight

241/6 - 55/4 = x

4 0
1 year ago
Solve for x in the equation x2 - 4x-9 = 29.
erastova [34]

Answer:

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

Step-by-step explanation:

One is given the following equation;

x^2-4x-9=29

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

x^2-4x-9=29

x^2-4x-38=0

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

ax^2+bx+c

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Substitute the coefficients of the given equation in and solve for the roots;

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}

Simplify,

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}

Therefore, the following statement can be made;

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

8 0
2 years ago
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