Sodium would form Na+
Oxygen would form O-2
Phosphorus would form -3 or +5
Sodium and oxygen would combine to form ionic bonds because one is a metal and the other is non-metal, while Phosporus and oxygen would combine to form covalent bonds because they are both non-metals.
Calculate the number of mole of 5O2:
1.2 x 5/4=1.5 mol
Answer:
The amount of heat released is 11.3 KJ
Explanation:
H20(g) -> H20(l) + heat
This reaction is changing state from gaseous to liquid without changing the temperature. This heat is know as Latent heat. It is the energy required for a phase change.
Heat released by 5 g of water vapor (Q) = M × L
where M = mass of vapor
L= latent heat
Latent heat can be divide into 2
- Latent heat of fusion
- Latent heat of vaporization
Since we are change the gaseous state to liquid, we will be working with Latent heat of vaporization which has a value of 22.6 x 10 ∧5 J/kg
(Q) = M × L
= 0.005 x 22.6 x 10 ∧5
= 11300 J
= 11.3 KJ
Answer:
d. A competitive inhibitor, collect kinetic daa both in the presence and absence of inhibitor and watch for a change in Km.
Explanation:
According to the description, the inhibitor was designed in a way when it binds the enzyme, the transition state achieved will be close to the one observed when the substrate binds.
In other words, the aim was to design an inhibitor that will bind the free enzyme in a reversible way, competing with the substrate for the binding sites.
As the inhibitor will be binding the same site as the substrate, the apparent affinity of the enzyme for the substrate will decrease. And the higher the affinity of the inhibitor for the enzyme, stronger the effect it will have over the affinity of the enzyme for the substrate.
Quantitatively speaking, the apparent Km of the enzyme for the substrate will increase with the inhibitor concentration, as the affinity of the enzyme for the substrate decreases.
In summary, what is being engineered is a competitive inhibitor, and the way of knowing if the design was successful, is collecting kinetic data in presence and absence of inhibitor, and watch for changes in the apparent Km.
Answer:
40 g/mL
Explanation: i did it and got it right
