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mihalych1998 [28]
3 years ago
7

On a cool morning, Uyen’s breath can form a cloud when she breathes out. Which changes of state are most responsible for Uyen se

eing her breath in this way?
melting
condensation
deposition
sublimation
Chemistry
2 answers:
Dima020 [189]3 years ago
8 0
Condensation because condensation is a process of freezing
sergiy2304 [10]3 years ago
7 0
The 2nd one is the correct answer
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Who was the scientist responsible for the discovery of the keystone species
sveticcg [70]

Answer:

Ecologist Robert Paine

Explanation:

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3 0
3 years ago
How do you Calculate the molarity of 250 ml of solution in which 2.7 g of MgCl2 are dissolved
IRINA_888 [86]

Answer:

Molar mass of MgCl2 is 95 g/mol

Mg = 24 g/mol and Cl = 35.5 ×2 = 71 g/mol

moles = mass given/ molar mass

= 2.7/95 = 0.028 mol

volume = 250/1000 = 0.25 dm3 (ml is the same as dm3)

molarity of MgCl2 = moles/volume

= 0.028/0.25

= 0.112 mol/dm3

3 0
2 years ago
What is the mass of CO2 lost at 20 min from the limestone sample?
harkovskaia [24]

Answer:

The mass, CO2 and CO3 from the limestone sample is discussed below in details.

Explanation:

(A) mass loss of sample of limestone after 20 min

= 0.8437g-0.5979g = 0.2458 g

From the given reaction of limestone, 2 mol of the sample gives 2 moles of CO 2.

Therefore  

184.4 g ( molar mass of limestone) gives2× 44 g of carbon dioxide.

1 g of sample gives 88/184.4 g of carbon dioxide

Hence 0.2458 g sample gives

= 88/184.4 × 0.2458 g = 0.117 g carbon dioxide

(B) mole of CO 2 lost = weight/ molar mass

= 0.117 g / 44 g/mol =0.0027 mole

(C). 1 mol of limestone contain 2 mol of carbonate ion

From the reaction we know that carbonate ion of limestone is converted into carbondioxide

Hence lost carbonate ion = 0.2458 g

(D) we know that

1 mol limestone contain 1mol CaCO​​​ 3

Hence in sample present CaCO​​​ 3

= 1mole / 184.4 g × 0.8437 g= 0.00458 mol CaCO​​​3

8 0
3 years ago
How many hydrogen atoms are in 4.40 mol of ammonium sulfide
katrin2010 [14]
 The number  of hydrogen  atoms  that are  in 4.40  mol  of ammonium sulfide is  2.12 x10^25  atoms

      calculation
 find the number of moles  of Hydrogen  in ammonium sulfide  (NH4)2S

that is  4.40  x  number of hydrogen atoms in (NH4)2S ( 4x2= 8  atoms)

moles is  therefore=  4.40  x8= 35.2  moles

by  use of  Avogadro's law  constant

that is  1mole =  6.02 x10^23 atoms
         35.2  moles=?

by  cross multiplication
  {35.2 moles x 6.02 x10^23} /1 mole  = 2.12  x10^25  atoms
5 0
3 years ago
Read 2 more answers
A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to
katen-ka-za [31]
I wrote the answer on this paper and here is the calculations step by step

very sry the "V" must be replaced with 285 and the 285 must be replaced with "V" and the answer is 231.09 cm3. sorry for the inconvenience.

6 0
3 years ago
Read 2 more answers
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