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mihalych1998 [28]
3 years ago
7

On a cool morning, Uyen’s breath can form a cloud when she breathes out. Which changes of state are most responsible for Uyen se

eing her breath in this way?
melting
condensation
deposition
sublimation
Chemistry
2 answers:
Dima020 [189]3 years ago
8 0
Condensation because condensation is a process of freezing
sergiy2304 [10]3 years ago
7 0
The 2nd one is the correct answer
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At STP how many moles or helium would occupy a volume of 12 liters?
butalik [34]
1 mole ------------- 22.4 L ( at STP )
?? mole ---------- 12 L

12 x 1 / 22.4 => 0.5357 moles

hope this helps! 
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3 years ago
What effects does the concentration of reactants have on the rate of a reaction ?
Harlamova29_29 [7]

Question:

<em>What effects does the concentration of reactants have on the rate of a reaction?</em>

Answer:

<em>Reactant concentration. Increasing the concentration of one or more reactants will often increase the rate of reaction. This occurs because a higher concentration of a reactant will lead to more collisions of that reactant in a specific time period.</em>

<em>Increasing the concentration of reactants generally increases the rate of reaction because more of the reacting molecules or ions are present to form the reaction products. ... When concentrations are already high, a limit is often reached where increasing the concentration has little effect on the rate of reaction.</em>

Hope this helps, have a good day. c;


5 0
3 years ago
The atomic mass is equal to what?​
dsp73

Answer:

The mass number

Explanation:

I hope this helps.

4 0
3 years ago
Read 2 more answers
Jane is sliding down a slide. What kind of motion is she demonstrating?
Alex Ar [27]
Im pretty sure it would be kinetic <span />
8 0
3 years ago
The reaction 2a → a2​​​​​ was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if
katovenus [111]

The integrated rate law for a second-order reaction is given by:

\frac{1}{[A]t} =   \frac{1}{[A]0} + kt

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

<span>k =</span> the rate constant for the reaction


<u>Given</u>: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min


Hence, \frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180)

<span>                                        = 4.858</span>

<span><span><span>Therefore, [A]</span>t</span>= 0.2058 M.</span>

<span>
</span>

<span>Answer: C</span>oncentration of A, after 180 min, is 0.2058 M

7 0
3 years ago
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