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Dmitrij [34]
2 years ago
13

7y + 7(3 − y) > 2y − 9

Mathematics
2 answers:
Zigmanuir [339]2 years ago
5 0

Answer:

y < 15

Step-by-step explanation:

7y + 7(3 − y) > 2y − 9 (Given)

7y + 21 - 7y > 2y - 9 (distributive property of inequality)

21 > 2y - 9 (combine like terms)

-2y > -30 (subtraction property of inequality)

y < 15 (division property of inequality) (sign changes side because it was divided by a negative number).

<u><em>Ace Carlos</em></u>

exis [7]2 years ago
3 0

Answer:

y < 15

Step-by-step explanation:

Simplify both sides of the inequality

Flip the equation

Add 9 to both sides

Divide both sides by 2

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Step-by-step explanation:

You can take 7yz common from all the terms in the given expression

Answered by GAUTHMATH

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3 years ago
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What is true of the function g(x)=-2x^2+5?
mart [117]

Answer:

C) The variable x represents the independent variable.

Step-by-step explanation:

The given function is g(x)=-2x^2+5.

g(x) is NOT the multiplication of g and x because g is a function of x.

x is the input of the function.

-2x^2+5 is the output of the function.

The variable x is called the independent variable because we plug in values of x to find g.

The variable g represents the output of the function NOT the input.

The correct choice is C

8 0
3 years ago
You are buying carpet to cover a room that measures 42 ft by 42 ft. The carpet cost $ 25 per square yard. How much will the carp
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3 0
2 years ago
Find the value of A if the 4-digit number 3A5A is divisible by both 3 and 5.
Arturiano [62]

Answer:

The value of A is 5

Step-by-step explanation:

- The number is divisible by 3 if the sum of its digits is a number

  divisible by 3

- Ex: 126 is divisible by 3 because the sum of its digits = 1 + 2 + 3 = 6

  and 6 is divisible by 3

- The number is divisible by 5 if its ones digit is zero or 5

- Ex: 675 is divisible by 5 because its ones digit is 5

        890 is divisible by 5 because its ones digit is 0

- We are looking for the value of A in the 4-digit number 3A5A which

  makes the number divisible by both 3 and 5

∵ A is in the ones position

∴ A must be zero or 5

- Let us try A = 0

∵ A = 0

∴ The number is 3050

∵ The sum of the digits of the number = 3 + 0 + 5 + 0 = 8

∵ 8 is not divisible by 3

∴ 3050 is not divisible by both 3 and 5

∴ A can not be zero

- Let us try A = 5

∵ A = 5

∴ The number is 3555

∵ The sum of the digits of the number = 3 + 5 + 5 + 5 = 18

∵ 18 is divisible by 3

∴ 3555 is divisible by both 3 and 5

∴ A must be equal 5

* <em>The value of A is 5</em>

5 0
3 years ago
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