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blagie [28]
3 years ago
15

Help me with this question please! (Look at image!)

Mathematics
2 answers:
Aleksandr [31]3 years ago
6 0
X^2 < 81
x< -9 and x > 9 
means
-9 < x < 9

A. -9 < 6  < 9 True
B. -9 < 9  < 9 False ( 9 = 9)
C. -9 < 10 < 9 False ( 10>9)
D. -9 < -4 < 9 True
E. -9 < -9 < 9 False ( -9 = -9)
F. -9 < -12 < 9 False ( -12 < -9)

so answer 
A. 6
D. -4
castortr0y [4]3 years ago
3 0
A and D are the solutions that make the inequality true.
6^2= 36
9^2= 81
10^2= 100
-4^2= 16
-9^2+ 81
-12^2= 144
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Find the cosine of ∠J.
SOVA2 [1]
Hope this helps (:


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6 0
2 years ago
Look at the right triangle ABC:
prisoha [69]

Answer:

The first incorrect justification is in step 2.

Step-by-step explanation:

<u>Step 2</u>. BC2 = AC • DC  

2. BC ÷ DC = BC ÷ AC because triangle ABC is similar to triangle BDC

It's supposed to be AC ÷ BC not BC ÷ AC.

8 0
3 years ago
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Oliga [24]

Answer:

\displaystyle 1)48.2    \:  \: \text{sec}

\rm \displaystyle  2)3021.6 \: m

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

\displaystyle  - 4.9 {t}^{2}  + 229t + 346 = 0

to solve the equation can consider the quadratic formula given by

\displaystyle x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4 ac} }{2a}

so let our a,b and c be -4.9,229 and 346 Thus substitute:

\rm\displaystyle t =  \frac{ - (229) \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

remove parentheses:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

simplify square:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}

simplify multiplication:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 6781.6} }{ - 9.8}

simplify Substraction:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 45659.4} }{ - 9.8}

by simplifying we acquire:

\displaystyle t = 48.2  \:  \:  \: \text{and} \quad  - 1.5

since time can't be negative

\displaystyle t = 48.2

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

\displaystyle x _{  \text{max}} =  \frac{ - b}{2a}

let a and b be -4.9 and 229 respectively thus substitute:

\displaystyle t _{  \text{max}} =  \frac{ - 229}{2( - 4.9)}

simplify which yields:

\displaystyle t _{  \text{max}} =  23.4

now plug in the maximum t to the function:

\rm \displaystyle  h(23.4)- 4.9 {(23.4)}^{2}  + 229(23.4)+ 346

simplify:

\rm \displaystyle  h(23.4)  =  3021.6

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

5 0
2 years ago
You're ordering a sandwich at the local deli, below is a tree diagram of the possible orders. What is the probability that your
dusya [7]

Answer:

Step-by-step explanation:

1. So there is two bread options but let's ignore that due every option being the same for both bread options.

2. So if you look there are three meat options meaning there is a one in three chance logical chance someone picks turkey (note when I say logical I mean that doesn't mean that this will be true in real life) and there is a one in two logical chance someone picks Swiss cheese.

3. So with a one in three chance logical meat option and a one two chance cheese option and.

4. Now knowing this it is simple math at this point as simple as \frac{1}{3} x \frac{1}{2}

5. 1 x 1 = 1 and 3 x 2 = 6

6. leading to \frac{1}{6}

4 0
2 years ago
- Find the slope-intercept form of the equation of the line that passes through (-5, 3) and is parallel to 12x – 3y = 10.
a_sh-v [17]
I’m pretty sure the answer is C. I’m not entirely sure.
8 0
3 years ago
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