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vova2212 [387]
3 years ago
13

Find the sixth term of a geometric sequence with which a, =-3 and r=-2.​

Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0

Answer: 96

Step-by-step explanation: a is the initial term, and r is the ratio by which a increases. Multiplying -2 by -3 five times gives this sequence: -3, 6, -12, 24, -48, 96

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Solomon has read 1/3 of his book. He finishes the book by reading the same amount each night for 5 nights. A. What fraction of t
Tatiana [17]
A) 2/3 divided by 5/1
= 2/3 X 1/5
= 2/15 of the book

B) 14X5=70
1/3
2/3
3/3
70+35= 105 pages
4 0
3 years ago
Graph this equation 3x+4y=12
Burka [1]
3x+4y=12 \ \ |\ subtract\ 3x\ to\ both\ sides \\\\ 4y=-3x+12 \ \ | \ divide \ both \ sides\ by\ 4\\\\ y=-\frac{3}{4}x+3\\\\x=-4 \ \ \to \ \ y= -\frac{3}{4}x+3=-\frac{3}{4} \cdot (-4)+3=3+3=6\\\\x=8 \ \ \to \ \ y= -\frac{3}{4}x+3=-\frac{3}{4} \cdot8+3=-6+3=-3


6 0
4 years ago
China was isolated because of
rusak2 [61]

Answer: D

Step-by-step explanation:

5 0
3 years ago
Hamad made a cuboid of size 2cm X 3cm X 4cm. How many such cuboids will be required to make a cube?
bonufazy [111]

Answer:

576 cuboids

Step-by-step explanation:

Let

x -----> the length side of the cube

n -----> number of cuboids that are needed

we know that

The volume of the cuboid is equal to

V=(2)(3)(4)=24\ cm^{3}

The volume of the cube is equal to

V=x^{3}

Find the number of cuboids that are needed

(n)24=x^{3}}

n*24 must be a perfect cube

so

The minimum value that satisfied n to make n*24 a perfect cube is n=576

576*24=13,824=24^{3}

6 0
3 years ago
Which expression uses the greatest common factor and the distributive property to rewrite the sum 42 + 72?
wlad13 [49]

Answer:

The answer is 6(7 + 12) ⇒ 1st answer

Step-by-step explanation:

* Lets explain how to solve the problem

- Factors are the numbers you multiply together to get another number

- Ex: 4 × 5 = 20 ⇒ 4 and 5 are the factors of 20

- Factors of a number n are the numbers that can multiplied together

 to give the number n

- Ex: The factors of 6 are 1 , 2 , 3 , 6 because 1 × 6 = 6 and 2 × 3 = 6

- The distributive property lets you multiply a sum by multiplying each

  term separately and then add the products

- Ex: a(b + c) = ab + ac

* Lets solve the problem

- We want to find the greatest common factor in 42 + 72

∵ 42 = 1 × 42 , 2 × 21 , 3 × 14 , 6 × 7

∴ The factors of 42 are 1 , 2 , 3 , 6 , 7 , 14 , 21 , 42

∵ 71 = 1 × 72 , 2 × 36 , 3 × 24 , 4 × 18 , 6 × 12 , 8 × 9

∴ The factors of 72 are 1 , 2 , 3 , 4 , 6 , 8 , 9 , 12 , 18 , 24 , 36 , 72

- The common factors between 42 and 72 are the bold numbers

∵ The common factors between 42 and 72 are 1 , 2 , 3 , 6

∵ The greatest one of them is 6

∴ The greatest common factor of 42 and 72 is 6

- In the distributive property we have a number multiplying by a sum

 of two numbers

∵ 42 ÷ 6 = 7 and 72 ÷ 6 = 12

- We can write 42 + 72 as 6 × 7 + 6 × 12 and take 6 as a common factor

∵ 42 + 72 = 6 × 7 + 6 × 12

- Take 6 as a common factor

∴ 42 + 72 = 6(7 + 12)

6 0
3 years ago
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