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2 years ago

How many grams of potassium carbonate are needed to make 300ml of a 4.5M solution?

Chemistry

1 answer:

kenny6666 [7]2 years ago

4 0

Answer:

186.3g

Explanation:

4.5moles of K₂CO₃ is in 1000ml

? moles of K₂CO₃ is in 300 ml

(4.5 × 300)/ 1000 = 1.35 moles of K₂CO₃

1 mole of K₂CO₃ = (39 × 2) + 12 + (16 × 3) = 78 + 12 + 48 = 138g

1.35 moles of K₂CO₃ = ?

= (1.35 × 138)/1 = 186.3g

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What is the number of the lowest energy level that contains an f sublevel?

forsale [732]

Answer: n = 4.

Explanation:

1) The main energy level is represented by the principal (main) quantum number, n. It can be 1, 2, 3, 4, 5,6, or 7. It is the period number in the periodic table.

2) The next quantum number is the Azimuthal quantum number (ℓ), also known as angular quantum number. It indicates the subshell (sublevel) or type of orbital.

This quantun number may be:

s, p, d, or f.

3) For n = 1, there is only one ℓ number: 0; which is the orbital s

For n = 2, there are two possible ℓ numbers: 0 and 1; which are the orbitals s and p.

For n = 3, there are three possible ℓ numbers: 0, 1, and 2, which are the orbitals s, p, and d:

For n = 4, there are four possible ℓ numbers:0, 1, 2, and 3; which are the orbitals s, p, d, and f.

So, the f sublevel appears first time when n = 4, i.e the number of the lowest energy level that contains an f sublevel is 4.

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2 years ago

Strong bases are good conductors of:

Zepler [3.9K]

Answer:

B. Electricity

Explanation:

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2 years ago

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What is the name for the elements that have some properties of metals and some properties of non-metals

Andrej [43]

Answer: The metalloids are a unique group of elements that share properties of both metals and nonmetals.

Explanation: They're also called the semimetals because of the shared properties of these elements along the dividing line between metals and nonmetals.

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2 years ago

Under the right conditions aluminum will react with chlorine to produce aluminum chloride.

salantis [7]

Answer:

$m_{Al}=9.42gAl$

Explanation:

Hello there!

In this case, according to the given chemical reaction:

2 Al + 3 Cl2 --> 2 AlCl3

Whereas there is a 2:3 mole ratio of aluminum to chlorine; it will be possible for us to calculate the required grams of aluminum by using the equality 22.4 L = 1 mol, the aforementioned mole ratio and the atomic mass of aluminum (27.0 g/mol) to obtain:

$m_{Al}=11.727LCl_2*\frac{1molCl_2}{22.4LCl_2}*\frac{2molAl}{3molCl_2} *\frac{27.0gAl}{1molAl} \\\\m_{Al}=9.42gAl$

Regards!

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The region is located on an active oceanic plate

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