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SSSSS [86.1K]
3 years ago
10

6th grade science I mark as brainliest zoom in if needed

Chemistry
1 answer:
RideAnS [48]3 years ago
5 0
A is the correct answer m


Tell me if I’m right or wrong

Thank you and yeah that’s it please inform me djdjdendrd
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C2H6 + Cl* => C2H5* + HCl
Contact [7]

Answer:

C2H6 + Cl → C2H5 + HCl

equation is balanced

8 0
3 years ago
Which phrase describes a volcano that is not expected to erupt again?
Ludmilka [50]
Volcanoes which are not expected to erupt again is known as Extinct Volcanoes.
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3 years ago
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By mistake, a quart of oil was dumped into a swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm
kondor19780726 [428]

The oil slick thick = 1.256 x 10⁻⁴ cm

<h3>Further explanation</h3>

Volume is a derivative quantity derived from the length of the principal

The unit of volume can be expressed in liters or milliliters or cubic meters

The conversion is

1 cc = 1 cm3

1 dm = 1 Liter

1 L = 1.06 quart

<em>so for 1 quart = 0.943 L</em>

\tt 0.943~L=0.943\times 10^{-3}m^3

Volume of oil dumped = volume of swimming pool

\tt 0.943\times 10^{-3}~m^3=25\times 30\times h(h=thick)\\\\h=\dfrac{0.943\times 10^{-3}}{750~m^2}=1.257\times 10^{-6}~m=\boxed{\bold{1.256\times 10^{-4}~cm}}

3 0
3 years ago
Layers of sediment forming at the bottom of the ocean
Kruka [31]

Answer: The Process is Deposition

Explanation:

7 0
3 years ago
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A glass flask of volume 400cm is just filled with mercury at 0 degree ​
3241004551 [841]

<em>A glass flask of volume 400 cm³ is just filled with mercury at 0°C. How much mercury will  overflow when the temperature of the system rises to 80°C.​</em>

<em />

The volume of mercury that overflow is 5.376 cm³

<h3>Further explanation</h3>

Given

volume of glass = 400 cm³

Δt=80 °C - 0 °C = 80

Required

overflow volume

Solution

With an increase in the temperature of the substance, objects can expand. This expansion includes volume expansion.

Can be formulated

\tt V_t=V_o(1+\gamma.\Delta t)\\\\\Delta V=V_o.\gamma.\Delta t

Find volume expansion of glass and mercury

  • Glass(γ = 1.2.10⁻⁵ C⁻¹)

\tt \Delta V=400\times 1.2.10^{-5}.80=0.384~cm^3

  • Mercury(γ=1.8.10⁻⁴ C⁻¹)

\tt \Delta V=400\times 1.8.10^{-4}\times 80=5.76~cm^3

Overflow :

ΔV mercury - ΔV glass : 5.76-0.384 = 5.376 cm³

7 0
3 years ago
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